我知道这个问题之前已经问过了,我已经检查了Spring MVC的每条消息和406错误消息,并且我身边不知道如何解决这个问题,因为我已经尝试所有以前的答案都是第四。Spring MVC Restful 406不可接受的错误
这一个网络服务需要一个电子邮件地址,并返回一个JSON用户对象。我可以告诉你,单元测试很好。我知道我们通过了Spring Security,我们正在执行servlet ......现在唯一的问题是JSON输出......我不明白,我收到了这个错误消息。
所以,确切的说:
弹簧芯:4.2.4.RELEASE 春季安全:4.0.3.RELEASE 杰克逊更快的XML:2.6.5(核心,数据绑定,注释) 2.7.0没有按”不像是会工作尚未...
这里是用SpringMVC-servlet.xml中:
<context:annotation-config />
<context:component-scan base-package="com.agmednet.server.controller" />
<mvc:annotation-driven>
<mvc:message-converters register-defaults="true">
<bean class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter">
<property name="objectMapper">
<bean class="com.agmednet.server.HibernateAwareObjectMapper">
<property name="dateFormat">
<bean class="java.text.SimpleDateFormat">
<constructor-arg type="java.lang.String" value="yyyy-MM-dd HH:mm:ss.SSS"></constructor-arg>
</bean>
</property>
</bean>
</property>
</bean>
</mvc:message-converters>
</mvc:annotation-driven>
这里是控制器:
@Controller
@RequestMapping("/users")
public class UserAccountController
{
@Autowired
private UserAccountService userAccountService;
@RequestMapping(value = "/email/{email:.*}", method = RequestMethod.GET)
public @ResponseBody UserAccountEntity getByEmailAddress(@PathVariable("email") String email)
{
Object principal = SecurityContextHolder.getContext().getAuthentication().getPrincipal();
User user = null;
if (principal instanceof User)
{
user = ((User) principal)
}
UserAccountEntity userAccount = userAccountService.getByEmailAddress(email);
return userAccount;
}
}
正如你所看到的,我有Accept标头设置,我有@ResponseBody
注释。
我有一个SimpleCORSFilter
代码在此之上:
@Component
public class SimpleCORSFilter implements Filter
{
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException
{
HttpServletResponse response = (HttpServletResponse) res;
response.setHeader("Access-Control-Allow-Origin", "*");
response.setHeader("Access-Control-Allow-Methods", "POST, PUT, GET, OPTIONS, DELETE");
response.setHeader("Access-Control-Max-Age", "3600");
response.setHeader("Access-Control-Allow-Headers", "x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token");
chain.doFilter(req, res);
}
public void init(FilterConfig filterConfig){}
public void destroy(){}
}
正如你所看到的,此接受我的一个“openam_token”自定义标题,但有 “接受”和“内容类型”以及。
我从防火墙后面Linux中调用这个,所以我要SSH到机器,并执行此卷曲声明:
curl -v -i -X GET -H "openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*" -H "Content-Type: application/json, text/html" -H "Accept: application/json, text/html" backend.spring.mycompany.net:8080/services/api/users/email/[email protected]
所以,在这里就是我通过卷曲的发要求:
* Trying 10.0.4.107...
* Connected to backend.spring.agmednet.net (10.0.4.107) port 8080 (#0)
> GET /services/api/users/email/[email protected] HTTP/1.1
> User-Agent: curl/7.40.0
> Host: backend.spring.agmednet.net:8080
> openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*
> Content-Type: application/json, text/html
> Accept: application/json, text/html
这里是回应:
< HTTP/1.1 406 Not Acceptable
HTTP/1.1 406 Not Acceptable
< Server: Apache-Coyote/1.1
Server: Apache-Coyote/1.1
< Access-Control-Allow-Origin: *
Access-Control-Allow-Origin: *
< Access-Control-Allow-Methods: POST, PUT, GET, OPTIONS, DELETE
Access-Control-Allow-Methods: POST, PUT, GET, OPTIONS, DELETE
< Access-Control-Max-Age: 3600
Access-Control-Max-Age: 3600
< Access-Control-Allow-Headers: x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token
Access-Control-Allow-Headers: x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token
< Cache-Control: no-cache, no-store, max-age=0, must-revalidate
Cache-Control: no-cache, no-store, max-age=0, must-revalidate
< Pragma: no-cache
Pragma: no-cache
< Expires: 0
Expires: 0
< X-XSS-Protection: 1; mode=block
X-XSS-Protection: 1; mode=block
< X-Frame-Options: DENY
X-Frame-Options: DENY
< X-Content-Type-Options: nosniff
X-Content-Type-Options: nosniff
< Set-Cookie: JSESSIONID=76C4B28DD0B5D88EB9341944BDBCD045; Path=/services/; HttpOnly
Set-Cookie: JSESSIONID=76C4B28DD0B5D88EB9341944BDBCD045; Path=/services/; HttpOnly
< Content-Type: text/html;charset=utf-8
Content-Type: text/html;charset=utf-8
< Content-Language: en
Content-Language: en
< Content-Length: 1110
Content-Length: 1110
< Date: Wed, 20 Jan 2016 14:30:28 GMT
Date: Wed, 20 Jan 2016 14:30:28 GMT
<!DOCTYPE html>
<html><head>
<title>Apache Tomcat/8.0.30 - Error report</title>
</head>
<body>
<h1>HTTP Status 406 - </h1>
<div class="line"></div><p><b>type</b> Status report</p>
<p><b>message</b> <u></u></p>
<p><b>description</b>
<u>The resource identified by this request is only capable of generating
responses with characteristics not acceptable according to the request*
Connection #0 to host backend.spring.agmednet.net left intact
"accept" headers.</u></p>
<hr class="line"><h3>Apache Tomcat/8.0.30</h3></body></html>
归根结底,这是错误的MES以上列出的鼠尾草:
The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request* Connection #0 to host backend.spring.mycompany.net left intact
“接受”标题。
所以,我使用@ResponseBody
,我使用的是最新的Jackson 2.x版本。我正在按照以前的问题提出所有建议,但仍然无法实现这个目标。
任何帮助将不胜感激。
对于初学者,删除'@ EnableWebMvc'你已经拥有了' '。 –
如上所述,删除EnableWebMVC,为什么你想收到一个清晰的邮件地址作为路径变量..收到一个简单的字符串,并检查它是否是一个有效的电子邮件。其次,你不需要显式地添加生产和接受。 –
首先....网络服务没有检查电子邮件的有效性。这是基于我们需要的,我们传递一封电子邮件,然后我们在该字段上进行数据库查询并从中返回一个用户,这是一个业务需求!其次,我明白我不需要一个“产品”,但不接受“接受”,但我会删除它,看看它是否能解决我的问题。我添加他们的唯一原因是测试出来,看看是否能解决问题,但事实并非如此。如前所述,我已经从我的控制器中删除了@EnableWebMvc。所以,我现在正在测试过程中。 – tjholmes66