JS解构一些变量，而不是其他的JS或部分拆解

Question

是否有可能只解构我所需要的值，而不是所有的人：

当然

let {myVar, _ , lastVar} = {first:"I need this", second: "Not this", third:"I also need this"} 

Answer 1

是。

如果你有一个对象，如：{foo: 4, bar: 2}，只有foo要求：

let { foo } = {foo: 4, bar: 2}; 

这也将工作：

let {first: first, third: third} = {first:"I need this", second: "Not this", third:"I also need this"} 

Answer 2

是，

let { a } = { a: 'a', b: 'b', c: 'c' } 
// a is 'a' 

或

let { a, ...rest } = {a: 'a', b: 'b'., c: 'c' } 
// a is 'a' 
// rest is { b: 'b', c: 'c' } 

[编辑 - 与你的价值观]

let {first, third} = {first:"I need this", second: "Not this", third:"I also need this"} 
// if you really want to change the variable names 
let myVar = first, lastVar = third