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我试图通过套接字连接将数据从客户端发送到服务器。我成功发送第一个数据,但当我尝试发送第二个它永远不会发送,当我尝试发送第三个它给我Sockets.SocketException
我该如何解决?服务器/客户端套接字连接
服务器
byte[] buffer = new byte[1000];
IPHostEntry iphostInfo = Dns.GetHostEntry(Dns.GetHostName());
IPAddress ipAddress = iphostInfo.AddressList[0];
IPEndPoint localEndpoint = new IPEndPoint(ipAddress, 8080);
Socket sock = new Socket(ipAddress.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
sock.Bind(localEndpoint);
sock.Listen(5);
while (true) {
Socket confd = sock.Accept();
string data = null;
int b = confd.Receive(buffer);
data += Encoding.ASCII.GetString(buffer, 0, b);
Console.WriteLine("" + data);
confd.Close();
}
客户
byte[] data = new byte[10];
IPHostEntry iphostInfo = Dns.GetHostEntry(Dns.GetHostName());
IPAddress ipAdress = iphostInfo.AddressList[0];
IPEndPoint ipEndpoint = new IPEndPoint(ipAdress, 8080);
Socket client = new Socket(ipAdress.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
try {
client.Connect(ipEndpoint);
Console.WriteLine("Socket created to {0}", client.RemoteEndPoint.ToString());
while (true) {
string message = Console.ReadLine();
byte [] sendmsg = Encoding.ASCII.GetBytes(message);
int n = client.Send(sendmsg);
}
}
catch (Exception e) {
Console.WriteLine(e.ToString());
}
Console.WriteLine("Transmission end.");
Console.ReadKey();
因为在您的服务器上连接后,您会收到1个字符串,并关闭连接。 – BugFinder
但是我们不是再次打开吗? – Pareidolia
你的客户不显示任何形式的关闭...所以跟踪你的代码,它会告诉你什么是错的 – BugFinder