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我有一些数据,看起来像这样:如何操纵汇总表结果
A B
6 Often Often
7 Always Always
8 Rarely Rarely
9 Sometimes Often
structure(list(A = structure(c(5L, 6L, 3L, 4L), .Label = c("",
"Almost Never", "Rarely", "Sometimes", "Often", "Always"), class = c("ordered",
"factor")), B = structure(c(5L, 6L, 3L, 5L), .Label = c("", "Almost Never",
"Rarely", "Sometimes", "Often", "Always"), class = c("ordered",
"factor"))), .Names = c("A", "B"), row.names = 6:9, class = "data.frame")
使用总结,我得到每种类型的反对可能的响应响应的,这正是我想要的东西的计数:
A B
:0 :0
Almost Never:0 Almost Never:0
Rarely :1 Rarely :1
Sometimes :1 Sometimes :0
Often :1 Often :2
Always :1 Always :1
现在我想操纵这些数字来获得(经常+总是)/总回应。总结输出是字符输出,虽然 - 我可以分割冒号,但必须有更好的方法。
如何计算给定上述数据集的每个问题的常数+总回答的百分比?