SQL查询 - 指定如何选择特定列

预警：我不是SQL开发人员。我正在查看此查询并尝试修改它以解决结果问题。SQL查询 - 指定如何选择特定列

我有后续的查询该作品（语法）：

SELECT 
    MIN(issue_time) AS incident_time, 
    MIN(issue_status) AS issue_status, 
    MIN(monitor_start_time) AS monitor_start_time, 
    MAX(resolved_time) AS resolved_time, 
    incident_id, 
    MAX(model_handle) AS model_handle, 
    device_retrieval_id, 
    MAX(last_status_time) AS last_status_time, 
    MAX(last_analysis_time) AS last_analysis_time, 
    n.node_name, 
    MAX(last_problem_time) AS last_problem_time, 
    SUM(problem_count) AS problem_count 
FROM (
    SELECT 
     issue_time, issue_status, monitor_start_time, resolved_time, incident_id, 
     model_handle, device_retrieval_id, last_status_time, last_analysis_time, 
     last_problem_time, problem_count 
    FROM x_network_device_node_status 
    UNION 
    SELECT 
     issue_time, issue_status, monitor_start_time, resolved_time, incident_id, 
     model_handle, device_retrieval_id, last_status_time, last_analysis_time, 
     last_problem_time, problem_count 
    FROM x_network_device_node_status_hist 
    WHERE incident_id IN (
     SELECT DISTINCT incident_id 
     FROM (
      SELECT incident_id 
      FROM x_network_device_node_status 
      UNION 
      SELECT incident_id 
      FROM x_network_device_node_status_hist 
      WHERE issue_time >= '2016-12-10' 
     ) AS i 
    ) 
) AS x LEFT JOIN 
x_nodes AS n ON x.device_retrieval_id = n.node_retrieval_id 
GROUP BY incident_id, device_retrieval_id, node_name 
ORDER BY incident_time DESC;

最近我意识到，我们不应该选择MAX(resolved_time) AS resolved_time，而是应与被获取resolved_time每个incident_id从记录最近的issue_time。

例如，如果在数据库中记录特定incident_id的联盟：

╔═════════════════════════╦══════════════╦═════════════════════════╦═════════════════════════╦═════════════════════╦══════════════╦═════════════════════╦═════════════════════════╦═════════════════════════╦═════════════════════════╦═══════════════╗ 
║  issue_time  ║ issue_status ║ monitor_start_time ║  resolved_time  ║  incident_id  ║ model_handle ║ device_retrieval_id ║ last_status_time  ║ last_analysis_time ║ last_problem_time ║ problem_count ║ 
╠═════════════════════════╬══════════════╬═════════════════════════╬═════════════════════════╬═════════════════════╬══════════════╬═════════════════════╬═════════════════════════╬═════════════════════════╬═════════════════════════╬═══════════════╣ 
║ 2016-12-13 17:15:00.000 ║   1 ║ 2016-12-13 17:46:28.000 ║ 2016-12-13 18:16:34.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-13 18:16:34.000 ║ 2016-12-13 18:01:28.000 ║ NULL     ║    0 ║ 
║ 2016-12-13 18:15:00.000 ║   1 ║ NULL     ║ 2016-12-13 18:31:28.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-13 18:31:28.000 ║ NULL     ║ NULL     ║    0 ║ 
║ 2016-12-13 18:31:28.000 ║   2 ║ 2016-12-14 09:16:28.000 ║ 2016-12-15 08:31:30.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 08:31:30.000 ║ 2016-12-15 08:16:28.000 ║ 2016-12-15 08:16:28.000 ║    6 ║ 
║ 2016-12-15 08:30:00.000 ║   1 ║ 2016-12-15 10:01:31.000 ║ 2016-12-15 11:46:28.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 11:46:28.000 ║ 2016-12-15 11:31:31.000 ║ 2016-12-15 11:31:31.000 ║    3 ║ 
║ 2016-12-15 11:45:00.000 ║   1 ║ NULL     ║ 2016-12-15 12:01:31.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 12:01:31.000 ║ NULL     ║ NULL     ║    0 ║ 
║ 2016-12-15 12:00:00.000 ║   1 ║ 2016-12-15 12:16:28.000 ║ 2016-12-15 12:31:29.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 12:31:29.000 ║ NULL     ║ NULL     ║    0 ║ 
║ 2016-12-15 12:30:00.000 ║   1 ║ NULL     ║ 2016-12-15 13:01:31.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 13:01:31.000 ║ NULL     ║ NULL     ║    0 ║ 
║ 2016-12-15 13:01:31.000 ║   2 ║ 2016-12-15 16:46:28.000 ║ NULL     ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 22:31:28.000 ║ 2016-12-15 22:31:28.000 ║ 2016-12-15 17:31:28.000 ║    2 ║ 
╚═════════════════════════╩══════════════╩═════════════════════════╩═════════════════════════╩═════════════════════╩══════════════╩═════════════════════╩═════════════════════════╩═════════════════════════╩═════════════════════════╩═══════════════╝

我想结果是：

╔═════════════════════════╦══════════════╦═════════════════════════╦═══════════════╦═════════════════════╦══════════════╦═════════════════════╦═════════════════════════╦═════════════════════════╦════════════╦═════════════════════════╦═══════════════╗ 
║  incident_time  ║ issue_status ║ monitor_start_time ║ resolved_time ║  incident_id  ║ model_handle ║ device_retrieval_id ║ last_status_time  ║ last_analysis_time ║ node_name ║ last_problem_time ║ problem_count ║ 
╠═════════════════════════╬══════════════╬═════════════════════════╬═══════════════╬═════════════════════╬══════════════╬═════════════════════╬═════════════════════════╬═════════════════════════╬════════════╬═════════════════════════╬═══════════════╣ 
║ 2016-12-13 17:15:00.000 ║   1 ║ 2016-12-13 17:46:28.000 ║ NULL   ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 22:31:28.000 ║ 2016-12-15 22:31:28.000 ║ MyNodeName ║ 2016-12-15 17:31:28.000 ║   11 ║ 
╚═════════════════════════╩══════════════╩═════════════════════════╩═══════════════╩═════════════════════╩══════════════╩═════════════════════╩═════════════════════════╩═════════════════════════╩════════════╩═════════════════════════╩═══════════════╝

但是，相反，它是回来作为：

╔═════════════════════════╦══════════════╦═════════════════════════╦═════════════════════════╦═════════════════════╦══════════════╦═════════════════════╦═════════════════════════╦═════════════════════════╦════════════╦═════════════════════════╦═══════════════╗ 
║  incident_time  ║ issue_status ║ monitor_start_time ║  resolved_time  ║  incident_id  ║ model_handle ║ device_retrieval_id ║ last_status_time  ║ last_analysis_time ║ node_name ║ last_problem_time ║ problem_count ║ 
╠═════════════════════════╬══════════════╬═════════════════════════╬═════════════════════════╬═════════════════════╬══════════════╬═════════════════════╬═════════════════════════╬═════════════════════════╬════════════╬═════════════════════════╬═══════════════╣ 
║ 2016-12-13 17:15:00.000 ║   1 ║ 2016-12-13 17:46:28.000 ║ 2016-12-15 13:01:31.000 ║ 1427068756009427097 ║  85983911 ║   332265337 ║ 2016-12-15 22:31:28.000 ║ 2016-12-15 22:31:28.000 ║ MyNodeName ║ 2016-12-15 17:31:28.000 ║   11 ║ 
╚═════════════════════════╩══════════════╩═════════════════════════╩═════════════════════════╩═════════════════════╩══════════════╩═════════════════════╩═════════════════════════╩═════════════════════════╩════════════╩═════════════════════════╩═══════════════╝

来源

2016-12-15 blgrnboy

SELECT 
    MIN(issue_time) AS incident_time, 
    MIN(issue_status) AS issue_status, 
    MIN(monitor_start_time) AS monitor_start_time, 
    (SELECT TOP 1 xxx.resolved_time 
    FROM 
    (SELECT xx.issue_time,xx.resolved_time 
    FROM x_network_device_node_status xx 
    WHERE xx.incident_id=x.incident_id 
    UNION ALL 
    SELECT xx2.issue_time,xx2.resolved_time 
    FROM x_network_device_node_status_hist xx2 
    WHERE xx2.incident_id=x.incident_id) AS xxx 
    ORDER BY xxx.issue_time DESC) AS resolved_time, 
    incident_id,

来源

2016-12-15 23:52:33

虽然这个代码片断可以解决这个问题，它没有解释为什么不然怎么回答了这个问题。请[请提供您的代码解释]（// meta.stackexchange.com/q/114762/269535），因为这确实有助于提高帖子的质量。请记住，您将来会为读者回答问题，而这些人可能不知道您的代码建议的原因。 **举报人/评论者：** [仅限代码解答，例如downvote，请勿删除！]（// meta.stackoverflow.com/a/260413/2747593） –

我不知道的语法，但想法是使用CTE和查询它。

;WITH CTE AS 
(SELECT 
    issue_time, issue_status, monitor_start_time, resolved_time, incident_id, 
    model_handle, device_retrieval_id, last_status_time, last_analysis_time, 
    last_problem_time, problem_count 
FROM x_network_device_node_status 
UNION 
SELECT 
    issue_time, issue_status, monitor_start_time, resolved_time, incident_id, 
    model_handle, device_retrieval_id, last_status_time, last_analysis_time, 
    last_problem_time, problem_count 
FROM x_network_device_node_status_hist 
WHERE incident_id IN (
    SELECT DISTINCT incident_id 
    FROM (
     SELECT incident_id 
     FROM x_network_device_node_status 
     UNION 
     SELECT incident_id 
     FROM x_network_device_node_status_hist 
     WHERE issue_time >= '2016-12-10' 
    ) AS i 
) 
) 
SELECT 
MIN(issue_time) AS incident_time, 
MIN(issue_status) AS issue_status, 
MIN(monitor_start_time) AS monitor_start_time, 
(SELECT resolved_time FROM CTE WHERE issue_time = (SELECT MAX(issue_time) FROM CTE)) AS resolved_time, 
incident_id, 
MAX(model_handle) AS model_handle, 
device_retrieval_id, 
MAX(last_status_time) AS last_status_time, 
MAX(last_analysis_time) AS last_analysis_time, 
n.node_name, 
MAX(last_problem_time) AS last_problem_time, 
SUM(problem_count) AS problem_count 
FROM CTE AS x LEFT JOIN 
x_nodes AS n ON x.device_retrieval_id = n.node_retrieval_id 
GROUP BY incident_id, device_retrieval_id, node_name 
ORDER BY incident_time DESC;

来源

2016-12-15 23:42:14 bubu7te

SQL查询 - 指定如何选择特定列

回答

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