我想通过将这样的引用作为参数传递给构造函数来初始化保存对另一个类的引用的类的属性。但是,我收到一个错误:引用作为类成员初始化
“'TaxSquare :: bank'必须在构造函数库/成员初始值设定项列表中初始化”。 下面的类代码有什么错误?
#ifndef TAXSQUARE_H
#define TAXSQUARE_H
#include "Square.h"
class Bank;
class TaxSquare : public Square
{
public:
TaxSquare(int, int, Bank&);
virtual void process();
private:
int taxAmount;
Bank& bank;
};
#endif
#include <iostream>
#include "TaxSquare.h"
#include "Player.h"
#include "Bank.h"
using namespace std;
TaxSquare::TaxSquare(int anID, int amount, Bank& theBank) : Square(anID)
{
taxAmount = amount;
bank = theBank;
}
#ifndef BANK_H
#define BANK_H
class Bank
{
public:
Bank(int, int, int);
void getMoney(int);
void giveMoney(int);
void grantHouse();
void grantHotel();
private:
int sumMoney;
int numOfHouses;
int numOfHotels;
};
#endif
+1对于“初始化列表中未指定的内容获取默认初始化,并且没有引用的默认初始化,因为它们必须始终引用“ –