1
>> df
Foo Bar Number Date
0 abc None NaN NaT
1 abcdefg None NaN NaT
2 abcd this 1111222 3/8/2017
3 abcd that 1233336 3/3/2017
4 abcd what 1346554 3/3/2017
5 abcde that 8889995 3/9/2017
6 abcde this 1849552 3/8/2017
7 abcd that 7418652 3/3/2017
8 abcdef this 4865154 3/7/2017
>> df.groupby(['Foo']).size().reset_index(name='Total')
如果我这样做,该行被视为有一个值,它的确如此,我明白这一点。我不知道如何在Total中包含该行,但实际上并不计算无/ NaN/NaT值?如何从python groupby中排除NaN/NaT/None,但包含该行?
返回:
Foo Total
0 abc 1
1 abcd 4
2 abcde 2
3 abcdef 1
4 abcdefg 1
预期结果:
Foo Total
0 abc 0
1 abcd 4
2 abcde 2
3 abcdef 1
4 abcdefg 0
就是这样,谢谢!我还没有使用分类,但现在会检查出来。 – Mike
@Mike不客气! – miradulo