Hibernate持久性：列未找到

Question

我在获取Column时未发现错误，并且我无法弄清楚什么是错误的，因此我寻求帮助。

我需要生成一个列表Task，其中引用User和Project。 我正在使用h2数据库。

下面是表：

CREATE TABLE TASK.APP_USER (
id INT NOT NULL GENERATED ALWAYS AS IDENTITY, 
username VARCHAR(25) NOT NULL, 
firstName VARCHAR(25) NOT NULL, 
lastName VARCHAR(25) NOT NULL, 
password VARCHAR(32) NOT NULL, 
PRIMARY KEY (id) 
); 

CREATE TABLE TASK.PROJECT (
id INT GENERATED ALWAYS AS IDENTITY, 
name VARCHAR(50) NOT NULL, 
companyName VARCHAR(50) NOT NULL, 
PRIMARY KEY (id) 
); 

CREATE TABLE TASK.PROJECT_TASK (
id INT GENERATED ALWAYS AS IDENTITY, 
projectId INT NOT NULL, 
userId INT NOT NULL, 
description VARCHAR(500) NOT NULL, 
estimatedDurationHours INT NOT NULL, 
PRIMARY KEY (id), 
FOREIGN KEY (projectId) REFERENCES TASK.PROJECT(id), 
FOREIGN KEY (userId) REFERENCES TASK.APP_USER(id), 
); 

下面是DAO类：

@Repository 
public class TaskDaoHibernate implements TaskDao { 
public TaskDaoHibernate() { 
} 

@Autowired 
private SessionFactory sessionFactory; 

private Session getCurrentSession() { 
    return sessionFactory.getCurrentSession(); 
} 

@SuppressWarnings("unchecked") 
@Override 
public List<User> fetchAllUsers() { 
    return getCurrentSession().createQuery("from User").list(); 
} 

@Override 
public User fetchUserById(Integer userId) { 
    return (User) getCurrentSession().get(User.class, userId); 
} 

@SuppressWarnings("unchecked") 
@Override 
public List<Project> fetchAllProjects() { 
    return getCurrentSession().createQuery("from Project").list(); 
} 

@Override 
public Project fetchProjectById(Integer projectId) { 
    return (Project) getCurrentSession().get(Project.class, projectId); 
} 

@Override 
public void saveTask(Task task) { 
    getCurrentSession().save(task); 
     } 

@SuppressWarnings("unchecked") 
@Override 
public List<Task> fetchAllTasks() { 
    return getCurrentSession().createQuery("from Task").list(); 
} 

@Override 
public Task fetchTaskById(Integer taskId) { 
    return (Task) getCurrentSession().get(Task.class, taskId); 
} 

@Override 
public void editTask(Task task) { 
    getCurrentSession().update(task); 
     } 

public SessionFactory getSessionFactory() { 
    return sessionFactory; 
} 

public void setSessionFactory(SessionFactory sessionFactory) { 
    this.sessionFactory = sessionFactory; 
} 


} 

这里是同样的原理User类，我已经规划项目类：

@Entity 
@Table(name="TASK.PROJECT") 
public class Project implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = 1L; 

@Id 
@Column(name = "ID") 
@GeneratedValue 
private Integer id; 

@Column(name = "NAME") 
private String nazivProjekta; 

@Column(name = "COMPANYNAME") 
private String nazivTvrtke; 

@ManyToOne 
@JoinColumn(name="PROJECTID") 
private Task task; 

//setters, getters and overrided equal and hashcode methods 

最后一类是Task类：

@Entity 
@Table(name="TASK.PROJECT_TASK") 
public class Task implements Serializable { 

/** 
* 
*/ 
private static final long serialVersionUID = -4633753821563474175L; 

@OneToMany(mappedBy="id", fetch=FetchType.EAGER) 
private List<User> user; 

@OneToMany(mappedBy="id", fetch=FetchType.EAGER) 
private List<Project> project; 

@Column(name = "DESCRIPTION ") 
private String opisZadatka; 

@Column(name = "ESTIMATEDDURATIONHOURS") 
private Integer trajanje; 

@Id 
@Column(name = "ID") 
@GeneratedValue 
private Integer id; 

public Task(){ 

} 

这里是堆栈跟踪的beggining：

org.h2.jdbc.JdbcSQLException: Column "USER0_.USERID" not found; SQL statement: 
select user0_.ID as ID1_2_0_, user0_.ID as ID1_0_0_, user0_.ID as ID1_0_1_, user0_.FIRSTNAME as FIRSTNAM2_0_1_, user0_.USERNAME as USERNAME3_0_1_, user0_.LASTNAME as LASTNAME4_0_1_, user0_.USERID as USERID5_0_1_, task1_.ID as ID1_2_2_, task1_.DESCRIPTION as DESCRIPT2_2_2_, task1_.ESTIMATEDDURATIONHOURS as ESTIMATE3_2_2_ from TASK.APP_USER user0_ left outer join TASK.PROJECT_TASK task1_ on user0_.USERID=task1_.ID where user0_.ID=? [42122-176] 
at org.h2.message.DbException.getJdbcSQLException(DbException.java:344) 
at org.h2.message.DbException.get(DbException.java:178) 
at org.h2.message.DbException.get(DbException.java:154) 

我认为我已经发布的所有相关信息，但如果需要别的东西，我会很乐意将其添加

Answer 1

你Task实体有一个List<User>，期望您的User有@ManyToOne关系。

但是，您的表TASK.PROJECT_TASK有一个FK到TASK.APP_USER表。意思是，任务与用户有一个@ManyToOne关系，而不是相反。

Answer 2

你的映射是不正确的把你的表格描述作为真相的来源。

1. 从项目到任务的关系应该是OneToMany而不是ManyToOne。
2. 同样，从任务到项目关系应该是多对一，而不是一对多
3. 任务和用户之间的关系应该是多对一，而不是一对多