是否有可能在此查询中获得overall_score的总和？

所以我有一个链接表和这些链接的投票表。因此，例如，链接google.co.uk在链接表中有一条记录，然后在投票表中可以有四个投票记录，每个记录的得分为-1,1或2。我已经完成了对每个链接的投票进行总结的这个查询，但是有可能将同一个查询中的所有链接的所有得分相加，所以用户有一个得分？是否有可能在此查询中获得overall_score的总和？

SELECT *, SUM(v.vote_score) AS overall_score 
FROM mdl_link_critic_links l 
    JOIN mdl_link_critic_votes v on l.id = v.link_id 
WHERE l.user_id = '3' 
GROUP BY l.id

结果是一样

google.co.uk, user_id 3, overall_score 3 
ebay.co.uk , user_id 3, overall_score 4 
stackoverflow.com, user_id, 3, overall_score 10

，我想总结所有的总分，所以在这种情况下，这将是17

来源

2016-06-07 Rich

* “所以在这种情况下，这将是17” * - 你的意思是16. 3,3，3,4和3让16，不17. ;-) –

不，总和领域overall_score，3 + 4 + 10使17 :) – Rich

'WITH ROLLUP'它会给你null，null，17' – splash58

什么子查询？它看起来像这样或多或少：

SELECT x.user_id, SUM(overall_score) AS user_score 
FROM (
    SELECT *, SUM(v.vote_score) AS overall_score 
    FROM mdl_link_critic_links l 
    JOIN mdl_link_critic_votes v on l.id = v.link_id 
    GROUP BY l.id 
) AS x 
GROUP BY x.user_id;

来源

2016-06-07 14:32:49

SELECT l.id, l.name, v.user_id, v.vote_score AS user_score, o.overall_score 
FROM mdl_link_critic_links l 
JOIN mdl_link_critic_votes v ON v.link_id = l.id 
JOIN (SELECT v.link_id, SUM(v.vote_score) AS overall_score 
     FROM mdl_link_critic_votes v 
     GROUP BY v.link_id) o ON o.link_id = l.id

来源

2016-06-07 14:53:26

是否有可能在此查询中获得overall_score的总和？

回答

相关问题