如何获取和每一行的MySQL

Question

海兰我有2个表
一，应用
id | name | status
====================
1 | morvick | complete
2 | siti | prosess
3 | boby | complete
`

2.application_test
id | application_id | test_id | result
======================================
1 | 1 | 1 | 70
2 | 1 | 2 | 80
3 | 1 | 3 | 90
4 | 2 | 1 | 60
5 | 2 | 2 | 80
6 | 2 | 3 | 70
7 | 3 | 1 | 90
8 | 3 | 2 | 70
9 | 3 | 3 | 60
10| 3 | 4 | 80
我的问题是：
==================
1.我怎么能得到每个test_id的总和（结果）在哪里状态完成
2.我怎么能得到总和（每个为test_id结果），其中状态prosess

例如是这样的：
test_id | SUM(result = complete) | SUM(result = proses) |
1 | 90 | 50
2 | 80 | 40
3 | 90 | 60
4 | 80 | 70

Answer 1

尝试下面的query

SELECT test_id, 
SUM(IF(app.status='complete',apt.result,0)) AS complete_sum, 
SUM(IF(app.status='process',apt.result,0)) AS process_sum 
FROM application_test AS apt 
JOIN application AS app ON app.id=apt.application_id 
GROUP BY apt.test_id 

Answer 2

你可以试试两个查询，如果你在一个查询

SELECT test_id, 
SUM(IF(a.status='complete',result,0)) Completed , 
SUM(IF(a.status='process',result,0)) Process 
FROM application a 
JOIN application_test t 
ON a.id=t.application_id 
GROUP BY t.test_id