删除红宝石后从每行空格的字符串

谁能帮我，如何从在红宝石串的每一行删除尾随空格....例如：删除红宝石后从每行空格的字符串

str = "Hello everyone. \nHope you guys are doing good \nstrange i can't remove this spaces"

我试着rstrip，但它不适合我....可能必须尝试gsub ....我希望答案在下面wayy。

"Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"

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2015-07-10 Sheharose

rstrip在字符串的末尾剥离空格，而不是在每行的末尾。你可以使用正则表达式在每个'\ n'之前进行替换。 – jcoppens

str.split("\n").map(&:rstrip).join("\n")

它可能与正则表达式是可行的，但我更喜欢这种方式。

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2015-07-10 16:09:27 DickieBoy

这看起来很贵 – Yule

谢谢DickieBoy – Sheharose

您可以使用gsub!，这将改变接收器：使用另外一个gsub

str = "Hello everyone. \nHope you guys are doing good \nstrange i can't remove this spaces" 
str.gsub!(/\s\n/, "\n").inspect 
#=> "Hello everyone.\nHope you guys are doing good \nstrange i can't remove this spaces"

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2015-07-10 16:18:56 orde

或者这样

str.each_line.map(&:strip).join("\n") 
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"

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2015-07-10 16:28:42 engineersmnky

：

str.gsub(/\s+$/, '') 
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"

/\s+$/一个或多个空格匹配（\s+）就在之前换行符（$）

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2015-07-10 17:25:50 Stefan

删除红宝石后从每行空格的字符串

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