查找重复名称sql

2012-07-30 99 views 2 likes

SELECT COUNT(organization.ID) 
FROM organization 
WHERE name in (SELECT name FROM organization GROUP BY name HAVING count(name) >1) 
AND organization.APPROVED=0 
AND organization.CREATED_AT>'2010-07-30 10:30:21'

我试图找到重复项，但此查询需要很长时间大概5-6秒。有没有另一种方法，我可以找到重复，而不使用我的方法？谢谢。查找重复名称sql

子查询：0.28秒。一切都是5.98秒。

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2012-07-30 Marin

我你独自执行子查询，确实需要很长的时间呢？ 'SELECT name FROM organization GROUP BY name HAVING count（name）> 1' – bpgergo 2012-07-30 14:24:53

好吧，我会尽力谢谢。 – Marin 2012-07-30 14:25:21

回答

SELECT organization.name, COUNT(organization.ID) 
    FROM organization 
WHERE organization.APPROVED=0 
    AND organization.CREATED_AT>'2010-07-30 10:30:21' 
GROUP BY name 
HAVING count(organization.id) > 1;

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2012-07-30 14:24:17 tvm

所有的工作，我选择了一个帽子:) – Marin 2012-07-30 14:47:12

没有必要使用查询WHERE子句。您可以使用GROUP BY和HAVING条款来实现：

SELECT COUNT(o.ID) 
FROM organization o 
WHERE o.APPROVED=0 
    AND o.CREATED_AT>'2010-07-30 10:30:21' 
GROUP BY o.Name 
HAVING COUNT(o.name) > 1

来源

2012-07-30 14:25:33 Taryn

为什么不只是不喜欢它：

SELECT COUNT(organization.ID) 
FROM organization 
WHERE organization.APPROVED=0 
AND organization.CREATED_AT>'2010-07-30 10:30:21' 
GROUP BY organization.name 
HAVING count(organization.name) > 1;

来源

2012-07-30 14:25:37

查找重复名称sql

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