0
我有一个表id
,header
等。想给出一个名称从header
列到下拉列表中的每个值。现在,它只能说明价值,这是非常不舒服:给每个选项的名称值
<form method="POST" enctype="multipart/form-data" action ="uploadext.php">
<?php require_once('uploadext.php'); ?>
<div class="col-md-6"><input type="file" name="fileToUploadgp"></div>
<div class="col-md-6"><input type="file" name="fileToUploadpro"><br>
<?php
$dbc = mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME);
$query = "SELECT id, header FROM done_add";
$query1="SELECT header FROM done_add";
$data = mysqli_query($dbc, $query);
$data1=mysqli_query($dbc, $query1);
$array=[];
while ($row = mysqli_fetch_array($data)) {
$arrayid[] = $row['id'];
$arrayhead[]=$row['header'];
}
?>
<select name="selectlink">
<?php foreach ($arrayid as $arr) {?>
<option value = "<?php print($arr)?>"
} ?><?php print($arr) ?></option>
<?php } ?>
</select>
<input type="submit" value="Отправить файлы" name="submita">
</div>
</form>