2017-03-08 85 views
0

我想使用透视函数,但不知道如何将bi-weekly表中的字母替换为人名而不是查询结果。这是我的查询。将SQL Pivot应用于表的最佳方式是什么?

SELECT a.OCD, a.[f_name],a.[l_name],a.[ads_phone], b.wk1m, b.wk1t, b.wk1w, b.wk1r, b.wk1f, b.wk2m, b.wk2t, b.wk2w, b.wk2r, b.wk2f 
FROM [dbo].[tbl_teleworkers] as a 
inner join [dbo].[tbl_scheduled] as b ON a.pin = b.pin 
where ocd = '022' 

here is my result: 
OCD|f_name|l_name|ads_phone|wk1m|wk1t|wk1w|wk1r|wk1f|wk2m|wk2t|wk2w|wk2r|wk2f 
022|John |smith |111-1111 |M | | | R | | | | | | 
022|Jane |smith |222-2222 | | | | | | | | W | | 
022|Joe |smith |333-3333 |M | | | | F | | | | | 
022|Jim |smith |444-4444 | | T | | | | M | | | | 
022|Jill |smith |555-5555 |M | | W | | | | | | R | 

Here is what I'm looking to get: So instead of the letters of the week. I'm trying to display the person's name and phone number. 
wk1m |wk1t|wk1w|wk1r |wk1f|wk2m|wk2t|wk2w |wk2r|wk2f 
John | | |John | | | |  | | 
phone| | |phone| | | |  | | 
    | | |  | | | |Jane S| | 
    | | |  | | | |phone | | 
Joe | | 
phone| | 

任何帮助将不胜感激。 谢谢!

回答

1

我将忽略您的主题行中的问题,因为您的示例数据和所需输出根本不需要PIVOT。

您可以通过将每列设置为CASE表达式来获得所需的输出。在每个wk**列中,如果该值不为空,则返回名字的值,最后一个首字母(如果需要)和电话号码连接在一起。

+0

谢谢!你是对的!我想我只是在推翻它。 – xicano66

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