`使用SUM和GROUP BY将mySQL查询转换为SQLite

Question

我正在使用ajax调用远程运行mySQL查询并将数据作为数组返回的移动应用程序。我想使用SQLite 3和iPad在本地运行查询。以下是mySQL查询。我遇到麻烦查询SQLite中

工作

这是我的工作MySQL查询

SELECT 
expense_date.expenseDate, 
expenses.cost, 
SUM(expenses.cost) as total, 
expenses.name, 
category.category 
FROM expenses 
INNER JOIN category ON expenses.catID = category.catID 
INNER JOIN expense_date ON expenses.dateID = expense_date.dateID 
WHERE expense_date.expenseDate BETWEEN '#from#' AND '#tu#' 
    AND expenses.catID != '1F27C7A1-3E16-5087-A313-A47D286A77A5' 
    AND expenses.catID != 'DF64C183-5056-A816-1ACA94F902242B61' 
    AND expenses.userID = '#userID#' 
    AND expenses.accountID = '#accountID#' 
Group By expense_date.expenseDate 

修订版的MySQL声明。此语句工作在MySQL，但不是在SQLite的3

SELECT 
    expense_date.expenseDate, 
    SUM(expenses.cost) as total 
    FROM expenses 
    INNER JOIN expense_date ON expenses.dateID = expense_date.dateID 
    WHERE expense_date.expenseDate 
     BETWEEN '2014-08-01' AND '2014-08-31' 
     AND expenses.catID != '1F27C7A1-3E16-5087-A313-A47D286A77A5' 
     AND expenses.catID != 'DF64C183-5056-A816-1ACA94F902242B61' 
     AND expenses.userID = 'C4C73329-5056-A816-1AB4B9FAE08FDB77' 
     AND expenses.accountID = '46298719-C78A-4CCE-8ADD-A3FD948DF93E' 
     Group By expense_date.expenseDate 

这是查询的结果。 2014-08-21有两个值：2000.00和372.00，但它们被叠加在一起并作为2014-08-21的单个值返回。

2014-08-01 32.00 
2014-08-16 15.00 
2014-08-19 513.55 
2014-08-21 2372.00 
2014-08-22 525.00 
2014-08-25 34.55 
2014-08-27 52.78 
2014-08-31 30.00 

我需要将MySQL查询代码转换为SQLite。我做了一个谷歌搜索，发现了一些关于使用CASE的信息，但我不知道如何构造sql语句。您的帮助表示赞赏

Answer 1

这是解决我的问题的SQLite sql语句。

SELECT expense_date.expenseDate, 
SUM(expenses.cost) AS total 
FROM expenses INNER JOIN expense_date ON expenses.dateID = expense_date.dateID 
WHERE expense_date.expenseDate BETWEEN '"+from+"' AND '"+tu+"' 
AND expenses.catID <> '1F27C7A1-3E16-5087-A313-A47D286A77A5' 
AND expenses.catID <> 'DF64C183-5056-A816-1ACA94F902242B61' Group By expense_date.expenseDate 

感谢大家的帮助。

Answer 2

您的SQL查询实际上在MySQL中没有意义，因为几个选定的值是不确定的。你可以尝试这样的事情：

SELECT ed.expenseDate, SUM(e.cost) as total, 
     group_concat(e.name) as names, 
     group_concat(c.category) as categories 
FROM expenses e INNER JOIN 
    category c 
    ON e.catID = e.catID INNER JOIN 
    expense_date ed 
    ON e.dateID = ed.dateID 
WHERE ed.expenseDate BETWEEN '#from#' AND '#tu#' AND 
     e.catID <> '1F27C7A1-3E16-5087-A313-A47D286A77A5' AND 
     e.catID <> 'DF64C183-5056-A816-1ACA94F902242B61' AND 
     e.userID = '#userID#' AND 
     e.accountID = '#accountID#' 
Group By ed.expenseDate;