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我有这样的代码在我的Android应用程序：取2个视图中显示同时在Android的
private void showMyViews() {
mAnimation.cancel();
mAnimation.reset();
mAnimateionView.clearAnimation();
mAnimationView.setVisibility(View.GONE);
mOtherViewToHide.setVisibility(View.GONE);
mFirstViewToShow.setVisibility(View.VISIBLE);
mSecondViewToShow.setVisibility(View.VISIBLE);
}
但有时mSecondViewToShow mFirstViewToShow之前出现一点点。我怎样才能轻松地迫使这些视图同时出现？
某些代码是：
public class mFragment extends Fragment implements OnClickListener, com.squareup.picasso.Callback {
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.mFragment, null);
mFirstViewToShow = (RelativeLayout) view
.findViewById(R.id.mFirstViewToShow);
mSecondViewToShow = (RelativeLayout) view
.findViewById(R.id.mSecondViewToShow);
...
...
...
if (isConnected()) {
animateMagnifier();
updateUserLocation();
} else {
}
}
private void animateMagnifier() {
Thread mThread = new Thread(new Runnable() {
@Override
public void run() {
AppLog.Log(TAG, "ver si la lupa sirve");
if (getActivity() != null) {
getActivity().runOnUiThread(new Runnable() {
@Override
public void run() {
mAnimationView.setVisibility(View.VISIBLE);
animeMagnifier = AnimationUtils
.loadAnimation(getActivity(),
R.anim.translate_center_amim);
mAnimationView.startAnimation(animeMagnifier);
// Code use to repeat the animation
// See
// http://stackoverflow.com/questions/4480652/android-animation-does-not-repeat
animeMagnifier
.setAnimationListener(new AnimationListener() {
@Override
public void onAnimationStart(
Animation animation) {
}
@Override
public void onAnimationRepeat(
Animation animation) {
}
@Override
public void onAnimationEnd(
Animation animation) {
animeMagnifier = AnimationUtils
.loadAnimation(
getActivity(),
R.anim.translate_center_amim);
animeMagnifier
.setAnimationListener(this);
mAnimationView
.startAnimation(animeMagnifier);
}
});
}
});
}
}
});
mThread.start();
try {
mThread.join();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
private void updateUserLocation() {
...
...
...
sendDataToServer();
}
private void sendDataToServer() {
...
...
...
findPerson();
}
private void findPerson() {
new BackGroundTaskForFindPerson().execute();
}
private class BackGroundTaskForFindMatch extends
AsyncTask<String, Void, Void> {
@Override
protected Void doInBackground(String... params) {
try {
findPeopleResponse = mServices.makeHttpRequest(
Constant.find_people, Constant.methodeName,
findPeopleValuePairList);
Gson gson = new Gson();
...
...
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
try {
if (success) {
if (mFindPeople.getErrNum() == 2) {
// no one found
mFirstViewToShow.setVisibility(View.GONE);
mSecondViewToShow.setVisibility(View.GONE);
messageTextView.setText(R.string.no_one_near);
} else if (mFindPeople.getErrNum == 3) {
...
} else {
....
}
} else {
messageTextView.setText(R.string.no_one_new);
}
} catch (Exception e) {
....
}
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
}
由于绘图发生在UI线程上（与您现在正在使用的线程相同），因此此代码不可能像您所解释的那样运行。你是否更改代码中其他地方的这些视图的可见性？ – 2014-09-18 19:28:32
@DmitryZaitsev是的，我会根据不同的行为将视图更改为“可见”或“消失”。有“线程”的解决方案吗？或者这太复杂了？谢谢！ – 2014-09-18 19:50:36
不，只有涉及的主线程。你能发布所有其他更新可视性的代码吗？我想我知道为什么会发生这种情况，但我需要查看其余的代码。 – 2014-09-18 20:22:13