我已经有一些名单,看起来像这样的实体:休眠envers - 装载历史嵌套对象
@Entity
@Table(name = "HOME")
@Audited
public class House {
@Id
private Integer id;
@Version
@Column(name = "UPDATE_DATE", nullable = false)
private Date updateDate;
@Column(name = "DESCRIPTION", nullable = false)
private String description;
@Cascade(CascadeType.ALL)
@OneToMany(fetch = FetchType.LAZY, mappedBy = "home", orphanRemoval = true)
private Set<Room> rooms;
[...]
}
同时假定间实体看起来像这样:
@Entity
@Table(name = "ROOM")
@Audited
public class Room {
@Id
private Integer id;
@Version
@Column(name = "UPDATE_DATE", nullable = false)
private Date updateDate;
@Column(name = "NAME", nullable = false)
private String name;
@Cascade(CascadeType.ALL)
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="HOUSE", nullable=false)
private House house;
[...]
}
正如你看到的房间保存着瀑布。让我们去我的问题的核心...
PRECONDITINS:在房屋目标
当前数据:
House:
description: "red house"
rooms: [room1, room2]
在审核表中现有的数据:
--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE | DESCRIPTION |
+-----+---------+----+-----------------+-------------+
| 111 | 0 | 10 | 2015-08-3 12:00 | red house |
--- ROOM_A ---
| REV | REVTYPE | ID | UPDATE_DATE | NAME | HOUSE |
| 111 | 0 | 100 | 2015-08-3 12:00 | room1 | 10 |
| 111 | 0 | 110 | 2015-08-3 12:00 | room2 | 10 |
使用者步骤:
使用这些数据更新房屋对象(更改房屋描述):
House:
description: "blue house"
rooms: [room1, room2]
在此之后操作审核表看起来就像这样:
House:
description: "blue house"
rooms: [room1, room2, room3]
后:这些数据(不改变房屋目标,并添加一个房间)
--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE | DESCRIPTION |
+-----+---------+----+-----------------+--------------+
| 111 | 0 | 10 | 2015-08-3 12:00 | red house |
| 112 | 1 | 10 | 2015-08-3 12:30 | blue house |
--- ROOM_A ---
| REV | REVTYPE | ID | UPDATE_DATE | NAME | HOUSE |
| 111 | 0 | 100 | 2015-08-3 12:00 | room1 | 10 |
| 111 | 0 | 110 | 2015-08-3 12:00 | room2 | 10 |
更新房屋目标此操作审计表将如下所示:
--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE | DESCRIPTION |
+-----+---------+----+-----------------+--------------+
| 111 | 0 | 10 | 2015-08-3 12:00 | red house |
| 112 | 1 | 10 | 2015-08-3 12:30 | blue house |
--- ROOM_A ---
| REV | REVTYPE | ID | UPDATE_DATE | NAME | HOUSE |
| 111 | 0 | 100 | 2015-08-3 12:00 | room1 | 10 |
| 111 | 0 | 110 | 2015-08-3 12:00 | room2 | 10 |
| 113 | 0 | 120 | 2015-08-3 12:40 | room3 | 10 |
LOAD经审计的内部数据:
--- current result ---
HOUSE_A(last_rev) -> HOUSE_A(112) -> 'blue house' with room1 and room2
--- expected result ---
HOUSE_A(last_rev) -> HOUSE_A(113) -> 'blue house' with room1, room2 and room3
这里的问题是...
房屋最高版本是112,但我已经做了已保存版本113(转进入最后不是招操作”因为房屋对象没有改变,所以被添加到HOUSE_A)。我知道envers加载所有数据的房屋对象的修订版本少或相等。在这种情况下,最后的操作将不会被加载。问题是 - 加载这些类型操作(主对象没有更新)的唯一方法是在保存之前更新主对象(house)的最后更新日期,这样新的条目将被添加到HOUSE_A,其版本与ROOM_A中的版本相同?
在此之后“处理方法”审核表看起来就像这样......
--- HOUSE_A ---
| REV | REVTYPE | ID | UPDATE_DATE | DESCRIPTION |
+-----+---------+----+------------------+--------------+
| 111 | 0 | 10 | 2015-08-30 12:00 | red house |
| 112 | 1 | 10 | 2015-08-30 12:30 | blue house |
| 113 | 1 | 10 | 2015-08-30 12:40 | blue house |
--- ROOM_A ---
| REV | REVTYPE | ID | UPDATE_DATE | NAME | HOUSE |
+-----+---------+-----+------------------+-------+-------+
| 111 | 0 | 100 | 2015-08-30 12:00 | room1 | 10 |
| 111 | 0 | 110 | 2015-08-30 12:00 | room2 | 10 |
| 113 | 0 | 120 | 2015-08-30 12:40 | room3 | 10 |
您是否找到实现此目的的方法?我想这样做 –