遍历内嵌套的对象

这是我的目标：遍历内嵌套的对象

family_Data = { 
    "Family": [ 
     { 
      "id": "Family-15", 
      "members": 
      { 
       "Family-15-01": [{"Family Code": "Family-15-01","Gender": "Female", "Full Name" : "Evelyn Osei"}], 
       "Family-15-02": [{"Family Code": "Family-15-02","Gender": "Male", "Full Name" : "David Will"}], 
       "Family-15-03": [{"Family Code": "Family-15-03","Gender": "Male", "Full Name" : "Edwin Pan"}] 
      } 
     } 
    ] 
}

我想遍历“成员”的对象。

来源

2016-12-28 Drew

琐碎的使用嵌套的'$ .each'，但你尝试过什么？ –

提示：'family_Data.Family [0] .members'指的是你想循环的对象。 –

您可以使用'for（var key in family_Data.Family [0] .members）'循环获取所有键的对象 – VadimB

var family_Data = { 
 
"Family": [ 
 
{ 
 
"id": "Family-15", 
 
"members": { 
 
"Family-15-01": [{"Family Code": "Family-15-01","Gender": "Female", "Full Name" : "Evelyn Osei"}], 
 
"Family-15-02": [{"Family Code": "Family-15-02","Gender": "Male", "Full Name" : "David Will"}], 
 
"Family-15-03": [{"Family Code": "Family-15-03","Gender": "Male", "Full Name" : "Edwin Pan"}] 
 
} 
 
} 
 
] 
 
}; 
 
for(var key in family_Data.Family[0].members){ 
 
    console.log(family_Data.Family[0].members[key]); 
 
    }

来源

2016-12-28 16:14:01

太棒了！非常感谢。 – Drew

首先得到您的members对象。

var members = family_Data.Family[0].members;

然后遍历该对象。

for(var key in members){ 
    var member = members[key]; 
    // here we go. 
}

来源

2016-12-28 16:13:19 subash

Subash，您的代码可以正常工作，但是您可以帮助我删除Family代码。我想要这样的对象：“成员”：{{“家庭代码”：“家庭15-01”，“性别”：“女性”，“全名”：“Evelyn Osei”}]， [ {“家庭代码”：“家庭15-02”，“性别”：“男性”，“全名”：“大卫威尔”}]， [{“家庭代码”：“家庭15-03”， “性别”：“男性”，“全名”：“Edwin Pan”}] } – Drew

我已将自己排序为Subash。这就是我所做的。 var result = {}; member.forEach（x => {x.que] = x.ans; }）; – Drew

遍历内嵌套的对象

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