2011-04-21 38 views
0

我试图定义一个特定的接口为我所有的库实现,比仅仅是这样的:IRepository与IRepository <T>

public abstract class GeneralizedRepository 
{ 
    readonly IDataModel _Model; 

    public GeneralizedRepository(IDataModel Model) { 
     if (Model == null) 
      throw new NullReferenceException(); 
     _Model = Model; 
    } 

    public IDataModel DataModel { get { return _Model; } } 

    public abstract IEnumerable<T> GetAll<T>(); 
    public abstract T GetOne<T>(Func<T, bool> predicate); 

    public abstract bool Contains<T>(Func<T, bool> predicate); 
    public abstract void Add<T>(T entity); 
    public abstract void Update<T>(T entity); 
    public abstract bool Remove<T>(Func<T, bool> predicate); 
} 

这是一类,因为我得到的资料库有共同的实例的DataModel

现在我有具体的实现为:

public class DetailRep : GeneralizedRepository 
{ 
    public DetailRep(IDataModel Model) : base(Model) { } 
    public DetailRep(UnitOfWork Unit) : base(Unit.Model) { } 

    public override IEnumerable<T> GetAll<T>() { 
     throw new NotImplementedException(); 
    } 

    public override T GetOne<T>(Func<T, bool> predicate) { 
     throw new NotImplementedException(); 
    } 

    public override bool Contains<T>(Func<T, bool> predicate) { 
     throw new NotImplementedException(); 
    } 

    public override void Add<T>(T entity) { 
     throw new NotImplementedException(); 
    } 

    public override void Update<T>(T entity) { 
     throw new NotImplementedException(); 
    } 

    public override bool Remove<T>(Func<T, bool> predicate) { 
     throw new NotImplementedException(); 
    } 
} 

但它是一个详细库,我的意思是,我要全部更换牛逼的该类型详细

但错误是在编译时抛出:

类型参数声明必须是一个标识符不是一个类型

+0

问题的标题中的类型没有出现在问题中!?你能再次检查你的问题吗?并提供有关错误的更多详细信息。例如,产生错误的行?对基地(...)的呼叫是错误的,但在解释之前,我首先需要了解你真正想要的。 – Achim 2011-04-21 19:33:27

回答

2

声明你的抽象类作为通用:

public abstract class GeneralizedRepository<T> 
{ 
    readonly IDataModel _model; 
    public GeneralizedRepository(IDataModel model) 
    { 
     if (model == null) 
      throw new NullReferenceException(); 
     _model = model; 
    } 
    public IDataModel DataModel { get { return _model; } } 
    public abstract IEnumerable<T> GetAll(); 
    public abstract T GetOne(Func<T, bool> predicate); 
    public abstract bool Contains(Func<T, bool> predicate); 
    public abstract void Add(T entity); 
    public abstract void Update(T entity); 
    public abstract bool Remove(Func<T, bool> predicate); 
} 

而不是在你的派生类FIL l与您的类型Detail

public class DetailRep : GeneralizedRepository<Detail> 
{ 
    public DetailRep(IDataModel model) 
     : base(model) 
    { 
    } 
    public override IEnumerable<Detail> GetAll(){} 
    public override Detail GetOne(Func<Detail, bool> predicate){} 
    public override bool Contains(Func<Detail, bool> predicate){} 
    public override void Add(Detail entity){} 
    public override void Update(Detail entity){} 
    public override bool Remove(Func<Detail, bool> predicate){} 
} 
+0

但以这种方式,如果我有10个存储库,并且每个实现GeneralizedRepository ,其中T是内容的类型比存储库包含的编译器将生成GeneralizedRepository ,GeneralizedRepository ,.... GeneralizedRepository 。我只想要一个抽象类和10个派生类。 – anotherNeo 2011-04-21 21:05:13

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