从两个级联列表中获取最大值（DateTime）ORACLE

我正在为某件事而挣扎，而且没有太多时间来自己弄清楚。从两个级联列表中获取最大值（DateTime）ORACLE

我的查询：

Select distinct d.delivery_bay_code,dt.diary_type_desc, d.delivery_datetime, ddo.order_no , ddo.company_id_no, ddo.no_of_cartons, s.supplier_name, c.company_name, sk.sku_desc, (pod.deliver_not_after_date)||' '||(pod.deliver_not_before_date)as delivery_window 
    from diary d , dc_diary_order ddo , purch_order po ,purch_order_carton_sku pocs ,sku sk, purch_order_date pod,supplier s , diary_type dt , company c 
    where ddo.diary_entry_id_no = d.diary_entry_id_no 
     and po.order_no = ddo.order_no 
     and po.company_id_no = ddo.company_id_no 
     and s.supplier_id_no = po.supplier_id_no 
     and s.company_id_no = po.company_id_no 
     and dt.diary_type_code = d.diary_type_code 
     and c.company_id_no = po.company_id_no 
     and po.order_no = pocs.order_no 
     and pocs.sku_id_no = sk.sku_id_no 
     and po.company_id_no = 2 
     and ddo.order_no = 1999 
     order by delivery_datetime;

这个查询带回2条记录，其中只有delivery_window不同。例如13/APR/11 13/APR/11 and 12/APR/11 12/APR/11我希望它仅带回最大日期时间（最新日期）。

例如：select max(delivery_datetime) from diary;

现在，我已经尽了上面的查询是这样的：

select... max(pod.deliver_not_after_date)||' '||(pod.deliver_not_before_date)as delivery_window ... from

，但我得到的错误ORA-00937: not a single-group group function

来源

2013-03-19 Werner van den Heever

：那是SQL的基础上，如果你想最大记录中，你需要把非在你的查询中，你使用了不同的子句，它可以给你多个记录，那么如果你希望你可以使用分析函数，那么获得最大交付日期的标准是什么？ – 2013-03-19 08:29:31

仅供参考：最大值将应用仅限于max（date1）。您不会从日期范围中获取最大值（日期1）||' “|| DATE2。 – Art 2013-03-19 15:09:48

你缺少GROUP BY上pod.deliver_not_before_date，即引起错误消息。

select... max(pod.deliver_not_after_date)||' '||(pod.deliver_not_before_date)as delivery_window ... from ..... GROUP BY pod.deliver_not_before_date

当使用MAX()或任何其他分组的功能，不具有分组功能的所有其他列必须把你的SQL语句的GROUP BY一部分。

要获得只对每个订单，你可以使用类似的最晚日期行：

select * 
     from (
      Select distinct d.delivery_bay_code,dt.diary_type_desc, d.delivery_datetime, ddo.order_no , ddo.company_id_no, ddo.no_of_cartons, s.supplier_name, c.company_name, sk.sku_desc, (pod.deliver_not_after_date)||' '||(pod.deliver_not_before_date)as delivery_window 
      , max(pod.deliver_not_after_date) over (partition by ddo.order_no order by ddo.order_no) max_deliver_not_after_date 
      from diary d , dc_diary_order ddo , purch_order po ,purch_order_carton_sku pocs ,sku sk, purch_order_date pod,supplier s , diary_type dt , company c 
      where ddo.diary_entry_id_no = d.diary_entry_id_no 
      and po.order_no = ddo.order_no 
      and po.company_id_no = ddo.company_id_no 
      and s.supplier_id_no = po.supplier_id_no 
      and s.company_id_no = po.company_id_no 
      and dt.diary_type_code = d.diary_type_code 
      and c.company_id_no = po.company_id_no 
      and po.order_no = pocs.order_no 
      and pocs.sku_id_no = sk.sku_id_no 
      and po.company_id_no = 2 
      and ddo.order_no = 1999 
      order by delivery_datetime) 
     where deliver_not_after_date = max_deliver_not_after_date;

来源

2013-03-19 08:28:32 JWK

从两个级联列表中获取最大值（DateTime）ORACLE

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