1

我想从下面的json过滤相同颜色的对象,并且每个颜色值都包含两个值(颜色和数值)的组合,但我只是想根据颜色进行过滤。javascript - 按属性对数组中的元素进行分组

这里我曾尝试

var _ = require('underscore-plus'); 
var data = [{ 
"name": "jim", 
    "color": "blue 1", 
    "age": "22" 
}, { 
"name": "Sam", 
    "color": "blue 2", 
    "age": "33" 
}, { 
"name": "eddie", 
    "color": "green 1", 
    "age": "77" 
}, 
{ 
"name": "Dheeraj", 
    "color": "blue 3", 
    "age": "25" 
}, 
{ 
"name": "Suraj", 
    "color": "green 1", 
    "age": "25" 
} 
]; 

var result=_.groupBy(data,"color"); 
console.log(result) 

结果应当是具有相同颜色的对象阵列。

[{ "name": "jim", "color": "blue 1", "age": "22" }, 
{ "name": "Sam", "color": "blue 2", "age": "33" }, 
{ "name": "Dheeraj", "color": "blue 3", "age": "25" }] 

[{ "name": "Suraj", "color": "green 1", "age": "25" }, 
{ "name": "eddie", "color": "green 1", "age": "77" }] 
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过滤器?分组?请添加想要的结果。 –

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结果应该是具有相同颜色的对象的数组。 [{ “名”: “吉姆”, “颜色”: “青1”, “时代”: “22” },{ “名”: “山姆”, “颜色”:“蓝色2" , “年龄”: “33” },{ “名称”: “Dheeraj”, “颜色”: “蓝3”, “年龄”: “25” }] 和[{ “名”: “苏拉杰”, “颜色”: “绿1”, “时代”: “25” },{ “名”: “埃迪”, “颜色”: “绿1”, “age”:“77” }] –

回答

0

你可以组:

如果你想,而不是筛选,在问题中提到,您可以使用下划线filter方法。

var data = [{ "name": "jim", "color": "blue 1", "age": "22" }, { "name": "Sam", "color": "blue 2", "age": "33" }, { "name": "eddie", "color": "green 1", "age": "77" }, { "name": "Dheeraj", "color": "blue 3", "age": "25" }, { "name": "Suraj", "color": "green 1", "age": "25" }], 
 
    grouped = {}, 
 
    colors; 
 

 
data.forEach(function (a) { 
 
    var group = a.color.match(/^[a-z]+/i); 
 
    grouped[group] = grouped[group] || []; 
 
    grouped[group].push(a); \t \t \t 
 
}); 
 
colors = Object.keys(grouped); 
 
colors.forEach(function (color) { 
 
    console.log(color, grouped[color]); 
 
});
.as-console-wrapper { max-height: 100% !important; top: 0; }

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感谢妮娜它按预期工作,你能不能请解释一下代码。 –

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基本上它从'color'属性获取字母并将其用作对象的关键字。那么它会检查'grouped'中的属性是否存在,如果不存在,则为其分配一个空数组。稍后使用颜色的关键点将éterated数组的实际元素推送到“分组”对象。 –

0

您可以使用Jquery.grep()例如

var result = $.grep(data, function(n){ return n.color == "blue 3" })

0

只需使用groupBy功能用下划线文档here详见:

var result = _.groupBy(data, function(datum) { return datum.color; }); 

您需要提供一个要使用的函数,该函数将返回属性以将元素进行分组,这种情况下为颜色。通过颜色

var blueOne = _.filter(data, function(datum){ return datum.color == 'blue 1'; }); 
1

您可以将项目使用Array.prototype.reduce

var data = [{ 
 
    "name": "jim", 
 
    "color": "blue 1", 
 
    "age": "22" 
 
}, { 
 
    "name": "Sam", 
 
    "color": "blue 2", 
 
    "age": "33" 
 
}, { 
 
    "name": "eddie", 
 
    "color": "green 1", 
 
    "age": "77" 
 
}, { 
 
    "name": "Dheeraj", 
 
    "color": "blue 3", 
 
    "age": "25" 
 
}, { 
 
    "name": "Suraj", 
 
    "color": "green 1", 
 
    "age": "25" 
 
}]; 
 

 
var result = data.reduce(function(grouped, obj) { 
 
    var key = obj.color.split(' ')[0]; // get the color from the key 
 
    grouped[key] = (grouped[key] || []).concat(obj); // use the existing array or create a new array, add the object to it, and assign it to the grouped object 
 
    
 
    return grouped; // return the grouped object 
 
}, {}); 
 

 
console.log(result);

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这似乎是答案的一半。 – Redu

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请详细说明。 –

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为了进一步解释这个问题,以一种非常规的方式,给出了预期的结果,对他自己的问题发表评论,我想在结果上需要做更多的工作。 – Redu

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