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移动矩形我有一个灰度图像的平均值,我一直是能够在图像上显示的矩形提取ROI和计算标准偏差和平均。但是,当我移动矩形时,我注意到图像有错误的值,尤其是图像完全黑色的地方。在这个领域,我应该得到一个零均值和标准差。然而,即时通讯获得0的平均值和负值的标准差和这个黑色区域的其他点平均增加到平均值与光主导地区相同。我一直在努力想出一个解决方案。有什么想法可以帮助吗?我会很感激。我的代码为鼠标移动按钮和平均值和标准偏差张贴如下。谢谢。获得不正确的标准偏差,并用在VB2010
Private Sub PictureBox1_MouseDown(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles PictureBox1.MouseDown
Dim mean As Double = 0
Dim meancount As Integer = 0
Dim bmap As New Bitmap(400, 400)
bmap = PictureBox1.Image
Dim colorpixel As Color = bmap.GetPixel(e.X, e.Y)
' Dim pixels As Double = colorpixel.R + colorpixel.G + colorpixel.B
If e.Button = Windows.Forms.MouseButtons.Left AndAlso Rect.Contains(e.Location) Then
If (PictureBox1.Image Is Nothing) Or (PictureBox1.Height - (e.Y + SquareHeight) < 0) Or (PictureBox1.Width - (e.X + SquareWidth) < 0) Then
Else
Dim ROI As New Bitmap(400, 400)
Dim x As Integer = 0
Dim countx As Integer = 0
Dim county As Integer = 0
For i = e.X To (e.X + SquareWidth)
For j = (e.Y + x) To (e.Y + SquareHeight)
Dim pixelcolor As Color = bmap.GetPixel(i, j)
ROI.SetPixel(countx, county, pixelcolor)
mean = mean + pixelcolor.R + pixelcolor.G + pixelcolor.B
county += 1
meancount += 1
Next
county = 0
countx += 1
x = x + 1
Next
mean = mean/meancount
Dim SD = mean - 75
Dim area As Integer = (SquareHeight * SquareWidth)
Dim anotherForm As Form2
anotherForm = New Form2(mean, SD, area, 34)
anotherForm.Show()
End If
End If
' Catch ex As Exception
' MessageBox.Show(ex.Message())
' End Try
End Sub
Private Sub PictureBox1_MouseMove(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles PictureBox1.MouseMove
Rect.X = e.X + x
Rect.Y = e.Y + y
Rect.Width = SquareWidth
Rect.Height = SquareHeight
' Label1.Text = "XRect: " + Rect.X.ToString() + " YRect: " + Rect.Y.ToString() + " Xmouse " + e.X.ToString() + " Ymouse " + e.Y.ToString()
PictureBox1.Refresh()
End Sub
Private Sub PictureBox1_Paint(ByVal sender As System.Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles PictureBox1.Paint
e.Graphics.DrawRectangle(Pens.Red, Rect)
End Sub
Private Function StandardDeviation(ByVal image As Bitmap, ByVal mean As Double, ByVal meancount As Integer) As Double
Dim SD(SquareHeight * SquareWidth) As Double
Dim count As Integer = 0
For i = 0 To SquareWidth
For j = 0 To SquareHeight
Dim pixelcolor As Color = image.GetPixel(i, j)
SD(count) = Double.Parse(pixelcolor.R) + Double.Parse(pixelcolor.G) + Double.Parse(pixelcolor.B) - mean
count += 1
Next
Next
Dim SDsum As Double = 0
For i = 0 To count
SDsum = SDsum + SD(i)
Next
SDsum = SDsum/(SquareHeight * SquareWidth)
SDsum = ((SDsum)^(1/2))
Return SDsum
End Function
Private Sub PictureBox1_MouseClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles PictureBox1.MouseClick
Dim P As Point = e.Location
P = New Point
End Sub
我想它提高了平均的结果,但它的关闭一些。不过,我想问一个问题。鉴于我的标准偏差功能我如何传递到了newform看来,如果我能通过标准偏差功能到我的标准偏差值将是正确的平均=平均/ meancount 点心SD =平均值 - 75 昏暗的区域作为整数=(SquareHeight * SquareWidth) 昏暗anotherForm如窗体2 anotherForm =新窗体2(平均,SD,区域,34) anotherForm.Show() –