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中正常工作就像标题所示,我很难让printf()
和echo
部分代码正确输出文本。无法使用printf()或echo在php
这里的第一页,一张简单的表格:
<form action="WhoYouAre.html" method="post">
<Label>Name: <label><input type="text" name="name"><br>
<Label>Age: <label><input type="text" name="age"><br>
<Label>Address: <label><input type="text" name="address"><br>
<Label>State: <label><input type="text" name="state"><br>
<Label>Sex: <label><input type="text" name="sex"><br>
<input type="submit" value="Submit">
</form>
下面是针对的应该显示的信息页面的代码:
<?php
session_start(); ?>
<?php
$_SESSION['name'] = $_POST['name'];
$_SESSION['age'] = $_POST['age'];
$_SESSION['address'] = $_POST['address'];
$_SESSION['state'] = $_POST['state'];
$_SESSION['sex'] = $_POST['sex'];
printf("Your name is %s.
Your age is %d.
Your address is %s, in the state of %s.
Your gender is %s.", $_SESSION['name'], $_SESSION['age'],
$_SESSION['address'], $_SESSION['state'], $_SESSION['sex']);
if($_SESSION['sex'] == 'male')
echo "<body style='background: url(http://images.mentalfloss.com/sites/default/files/styles/article_640x430/public/4hjh3kj634.png)'>";
echo file_get_contents("PostPage.txt");
?>
下面是输出到我的网页。
"; echo file_get_contents("PostPage.txt"); ?>
任何提示??
可能重复的[PHP代码没有被执行,而是代码显示在页面上](http://stackoverflow.com/questions/5121495/php-code-is-not-being-executed-instead-code-显示 - 上的页面) –