-1
我有这样的JSON和我需要从它呼应了一些具体的结果与PHPECHO JSON用PHP
JSON
{
totalResultsCount: 1,
geonames: [
{
adminCode1: "06",
lng: "27.85849",
geonameId: 953781,
toponymName: "Soweto",
countryId: "953987",
fcl: "P",
population: 1695047,
countryCode: "ZA",
name: "Soweto",
fclName: "city, village,...",
countryName: "South Africa",
fcodeName: "populated place",
adminName1: "Gauteng",
lat: "-26.26781",
fcode: "PPL"
}
]
}
我将如何回应让说名字是在GEONAMES []
我想这
<?php
echo $json->geonams->name
?>
,因为我觉得它来接近我到底 –
得到望着JSON,我将标志着这个作为回答'$ json-> geonames'是一个数组,它使得1.'$ json-> geonames [0] - > name'和2. $ arr ['geonames'] [0] ['name]'。 –
geonames是一个子数组的集合,因此您需要@MagnusEriksson指出的[0]的索引。更新你的答案+1 – zanderwar