MySQL中的所有有一列的总和行

Question

我尝试创建一个查询来选择表中的所有行有一列名newtotal

的总和这是我的查询

SELECT * 
FROM tbl_activities 
     ,(SELECT SUM(db_newtotal) as total FROM tbl_activities) {$sql} 

{$ SQL}在这里列名=从SEACH表单输入

但我有此错误：

Every derived table must have its own alias

我试着这样做：

SELECT * 
FROM tbl_activities 
    ,(SELECT SUM(db_newtotal) as total FROM tbl_activities) as Table {$sql} 

但我有此错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Table where db_projectname='Barbara Bui'' at line 1

我打印查询，这是输出

SELECT * 
FROM tbl_activities 
    ,(SELECT SUM(db_newtotal) as total FROM tbl_activities) as Table 
where db_projectname='Barbara Bui' 

输出我想应该是这样的：以项目名称命名LL记录='Barbara Bui'用总和newtotal

projectname location Cost 
Barbara Bui verdun  100 
Barbara Bui kaslik  200 
Barbara Bui achrafieh 500 
Total      800 

查询

SELECT * FROM tbl_activities 
     union all 
     select db_id,db_category,db_subcategory,db_taskname,db_predecessors,db_unit,db_qty,db_wo,db_duration,db_startdate,db_enddate,db_asd,db_add,db_transferredto,db_prb,db_anotes,db_aduration,db_projectname,db_A,db_AA,db_AAA,db_cost,db_status,db_room,db_floor,db_date,sum(db_newtotal) as total from tbl_activities 
     {$sql} 

Answer 1

错误是因为table是保留关键字。

你想用UNION ALL这样的：

select projectname, location, cost 
from tbl_activities {$sql} 

union all 

select 'Total', null, sum(cost) 
from tbl_activities {$sql}; 

使用参数应用where子句，就变成：

select projectname, 
    location, 
    cost 
from tbl_activities {$sql} 

union all 

select 'Total', 
    null, 
    sum(cost) 
from tbl_activities {$sql} 

如果你在你的UNION的第一部分，更多的列ALL，然后确保第二个选择中的所有这些许多空值。

select db_id, db_category, db_subcategory, db_taskname, db_predecessors, db_unit, db_qty, db_wo, db_duration, db_startdate, db_enddate, db_asd, db_add, db_transferredto, db_prb, db_anotes, db_aduration, db_projectname, db_A, db_AA, db_AAA, db_cost, db_status, db_room, db_floor, db_date, db_newtotal 
from tbl_activities {$sql} 

union all 

select null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, sum(db_newtotal) 
from tbl_activities {$sql} 

Answer 2

表是大多数关系数据库管理系统保留字，所以你不能把它作为一个别名，尝试改变

SELECT * FROM tbl_activities,(SELECT SUM(db_newtotal) as total FROM tbl_activities) as myTable {$sql} 

，并看看是否能工程