MySQL - 组和总数，但返回每个组中的所有行

Question

我正在尝试编写一个查询，查找每次在特定日期范围内发生在我的表中的同一个人。然后它将这个人分组并且将他们的花费总计在特定范围内。如果他们的消费习惯大于X金额，则在指定的日期范围内为此人返回每一行。不仅仅是分组总量。这是我到目前为止：

SELECT member_id, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50 

这是检索正确的总和返回成员花费超过50美元，但不是每一行。只是每个成员的总数和他们的总数。我目前正在查询整个表格，我没有添加日期范围。

Answer 1

JOIN这个子查询与原表：

SELECT si1.* 
FROM sold_items AS si1 
JOIN (SELECT member_id 
     FROM sold_items 
     GROUP BY member_id 
     HAVING SUM(amount) > 50) AS si2 
ON si1.member_id = si2.member_id 

一般的规则是由同一列（S）的子查询组，它的选择，然后你加入那与原始查询我们在同一列。

Answer 2

有几种语法可以得到您要查看的结果，下面是使用内部联接来确保返回的所有行在由组返回的列表中具有member_id并且总计为每个某成员有：

SELECT si.*, gb.total from sold_items as si, (SELECT member_id as mid, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50) as gb where gb.mid=si.member_id; 

Answer 3

SELECT member_id, amount 
FROM sold_items si 
INNER JOIN (SELECT member_id, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50) spenders USING (member_id) 

您已经构建的查询可以用作临时表来加入。如果member_id不是表格中的索引，则这将随着比例变慢。 单词spenders是一个表别名，您可以使用任何有效的别名代替它。

Answer 4

我认为，这可能帮助：

SELECT 
    member_id, 
    SUM(amount) AS amount_value, 
    'TOTAL' as amount_type 
FROM 
    `sold_items` 
GROUP BY 
    member_id 
HAVING 
    SUM(amount) > 50 

UNION ALL 

SELECT 
    member_id, 
    amount AS amount_value, 
    'DETAILED' as amount_type 
FROM 
    `sold_items` 
    INNER JOIN 
    (
     SELECT 
      A.member_id, 
      SUM(amount) AS total 
     FROM 
      `sold_items` A 
     GROUP BY 
      member_id 
     HAVING 
      total <= 50 
    ) AS A 
    ON `sold_items`.member_id = A.member_id 

上述查询的结果应该是这样的：

member_id  amount_value amount_type 
========================================== 
1    55    TOTAL 
2    10    DETAILED 
2    15    DETAILED 
2    10    DETAILED 

所以列amount_type将区分两个特定成员组

Answer 5

你可以用EXISTS做子查询：

select * 
from sold_items t1 
where exists (
    select * from sold_items t2 
    where t1.member_id=t2.member_id 
    group by member_id 
    having sum(amount)>50 
) 

ref：http://dev.mysql.com/doc/refman/5.7/en/exists-and-not-exists-subqueries.html