帮助：达到客户端的最大数量 - 分段错误

Question

我想模拟许多按键事件。我使用XTestFakeKeyEvent找到了一个解决方案，但是当我模拟超过210次时，我的程序引发了“达到的最大客户端数量”分段错误。我不知道如何解决这个问题。

我的代码在这里：

#include <X11/Xlib.h> 
#include <X11/keysym.h> 
#include <X11/extensions/XTest.h> 
#include <stdio.h> 

#define PRESS_UP 0 
#define PRESS_DOWN 1 
#define PRESS_LEFT 2 
#define PRESS_RIGHT 3 
#define PRESS_ENTER 4 
#define PRESS_ESC 5 
#define PRESS_HOME 6 

Display *display; 
unsigned int keycode; 

int press(int key){ 
    display = XOpenDisplay(NULL); 

    if(key == PRESS_UP) 
     keycode = XKeysymToKeycode(display, XK_Up); 
    else if(key == PRESS_DOWN) 
     keycode = XKeysymToKeycode(display, XK_Down); 
    else if(key == PRESS_LEFT) 
     keycode = XKeysymToKeycode(display, XK_Left); 
    else if(key == PRESS_RIGHT) 
     keycode = XKeysymToKeycode(display, XK_Right); 
    else if(key == PRESS_ENTER) 
     keycode = XKeysymToKeycode(display, XK_Return); 
    else if(key == PRESS_ESC) 
     keycode = XKeysymToKeycode(display, XK_Escape); 
    else if(key == PRESS_HOME) 
     keycode = XKeysymToKeycode(display, XK_Home); 

    XTestFakeKeyEvent(display, keycode, True, 0); 
    XTestFakeKeyEvent(display, keycode, False, 0); 
    XFlush(display); 
    return 0; 
} 

int main(int argc, char *argv[]){ 
    int count = 0; 
    while (count < 500){ 
     press(PRESS_UP); 
     printf("count =%d\n" ,count); 
     count ++; 
    } 
} 

输出：

$ gcc -lXtst -lX11 Util_KeyPressSimulator.c 
$ ./a.out 
count =0 
^[[Acount =1 
^[[Acount =2 
... 
^[[Acount =208 
^[[Acount =209 
^[[Acount =210 
^[[AMaximum number of clients reachedSegmentation fault 

难道一个请帮忙，谢谢。

Answer 1

你在做一个XOpenDisplay每迭代没有匹配XCloseDisplay。考虑在循环之外打开显示屏main()一次，然后在退出之前将其关闭。