通过方法

Question

传递和返回两个不同的泛型类现在我使用Generic1的T，但可以理解，当我传入sPayload时会出错，因为我不确定如何指定第二个泛型类型。

public static Generic1 SendReceive<Generic1>(string sUrl, Generic2 sPayload) 
{ 
    using(WebClient webclient = new WebClient()) 
    { 
     webclient.Headers[HttpRequestHeader.ContentType] = "application/json"; 
     string response = webclient.UploadString(sUrl, JsonConvert.SerializeObject(sPayload)); 
     Generic1 parsedResponse = JsonConvert.DeserializeObject<Generic1>(response); 
     return parsedResponse; 
    } 
} 

我想避免使用条件语句，并在硬编码传递的潜在类型。我只是不知道该如何去这样做。

Answer 1

您需要在声明指定两种类型：

public static TResult SendReceive<TResult, TPayLoad>(string sUrl, TPayLoad sPayload) 
{ 
    using(WebClient webclient = new WebClient()) 
    { 
     webclient.Headers[HttpRequestHeader.ContentType] = "application/json"; 
     string response = webclient.UploadString(sUrl, JsonConvert.SerializeObject(sPayload)); 
     TResult parsedResponse = JsonConvert.DeserializeObject<TResult>(response); 
     return parsedResponse; 
    } 
} 

Answer 2

您可以用逗号将它们

public static TResponse SendReceive<TRequest,TResponse>(string sUrl, TRequest sPayload) 
{ 
    .... 
} 

Answer 3

分离指定多个泛型类型，您可以添加使用此这样

多个参数

public static T1 SendReceive<T1,T2,...Tn>(string sUrl, TRequest sPayload) 
{ 
    //TODO Code 
} 

然后你可以这样称呼它

className.SendResponse<Class1, Class2,...Classn>(...);