百分比值与GNU差异

Question

使用diff显示两个文件之间的百分比差异的好方法是什么？

例如，如果一个文件有100行，并且一个副本有15行已被更改，diff-percent将为15％。

Answer 1

也许这样的事情？

两个文件，A1和A2。

$ sdiff -B -b -s A1 A2 | wc会给你多少行不同。 wc给出总数，只是划分。

-b和-B将忽略空白和空行，并且-s表示禁止公用行。

Answer 2

这里有一个脚本，将比较所有.txt文件，并显示有超过15％的重复的那些：

#!/bin/bash 

# walk through all files in the current dir (and subdirs) 
# and compare them with other files, showing percentage 
# of duplication. 

# which type files to compare? 
# (wouldn't make sense to compare binary formats) 
ext="txt" 

# support filenames with spaces: 
IFS=$(echo -en "\n\b") 

working_dir="$PWD" 
working_dir_name=$(echo $working_dir | sed 's|.*/||') 
all_files="$working_dir/../$working_dir_name-filelist.txt" 
remaining_files="$working_dir/../$working_dir_name-remaining.txt" 

# get information about files: 
find -type f -print0 | xargs -0 stat -c "%s %n" | grep -v "/\." | \ 
    grep "\.$ext" | sort -nr > $all_files 

cp $all_files $remaining_files 

while read string; do 
    fileA=$(echo $string | sed 's/.[^.]*\./\./') 
    tail -n +2 "$remaining_files" > $remaining_files.temp 
    mv $remaining_files.temp $remaining_files 
    # remove empty lines since they produce false positives 
    sed '/^$/d' $fileA > tempA 

    echo Comparing $fileA with other files... 

    while read string; do 
     fileB=$(echo $string | sed 's/.[^.]*\./\./') 
     sed '/^$/d' $fileB > tempB 
     A_len=$(cat tempA | wc -l) 
     B_len=$(cat tempB | wc -l) 

     differences=$(sdiff -B -s tempA tempB | wc -l) 
     common=$(expr $A_len - $differences) 

     percentage=$(echo "100 * $common/$B_len" | bc) 
     if [[ $percentage -gt 15 ]]; then 
      echo " $percentage% duplication in" \ 
       "$(echo $fileB | sed 's|\./||')" 
     fi 
    done < "$remaining_files" 
    echo " " 
done < "$all_files" 

rm tempA 
rm tempB 
rm $all_files 
rm $remaining_files 

Answer 3

https://superuser.com/questions/347560/is-there-a-tool-to-measure-file-difference-percentage有这很好地解决，

wdiff -s文件1。 txt file2.txt

更多选项请参阅man wdiff。