从字符串正则表达式删除字符串

Question

我有一个自动生成的字符串，如下所示：

["January","February",null,"April"] 

我需要从字符串中删除的“空”任何比赛，即：

["January","February",null,"April"] --> ["January","February","April"] 

我怎样才能找到除",null"之外的所有东西？

我试过"^(?!,null).*"的变体没有成功。

Answer 1

要回答你的问题是说，你不需要正则表达式：

str = str.replace(",null", ""); 

然而，处理边界情况太：

["January","February",null,"April"] --> ["January","February","April"] 
["January",null,null,"April"] --> ["January","April"] 
[null,"January","February","April"] --> ["January","February","April"] 
["January","February","April",null] --> ["January","February","April"] 
[null] --> [] 

你会可以更好地与正则表达式服务：

str = str.replaceAll("(?<=\\[)null,?|,null", ""); 

更换正则表达式迎合f或第一个（也可能是唯一的）职位，以及任何其他情况。

Answer 2

请仔细阅读这一块，我们可以使用过滤功能

var arr = [null, "January","February",null,"April", null]; 
 

 
var arr2 = arr.filter(function(x){return x !== null}) 
 

 
console.log(arr,arr2);