XSLT把XML转换成CSV和重复同胞对每条记录

Question

下面是用作源XML文件：

<?xml version="1.0" encoding="UTF-8" ?> 
<billing-log> 
    <log-start-date>2012-08-17T00:00:00-05:00</log-start-date> 
    <player-name>Player1</player-name> 
    <schema-version>1</schema-version> 
    <player-uuid>12345</player-uuid> 
    <log-end-date>2012-08-17T23:59:59.999-05:00</log-end-date> 
    <entry> 
    <page>Page1</page> 
    <path>Path1</path> 
    <in>2012-08-16T23:59:52.170-05:00</in> 
    <out>2012-08-17T00:00:00.186-05:00</out> 
    </entry> 
    <entry> 
    <page>Page2</page> 
    <path>Path2</path> 
    <in>2012-08-17T00:00:00.186-05:00</in> 
    <out>2012-08-17T00:00:08.561-05:00</out> 
    </entry> 
</billing-log> 

我使用XSL文件是这样的：

<?xml version="1.0"?> 
<xsl:stylesheet version = "1.0" xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="text"/> 
    <xsl:template match="log-start-date"></xsl:template> 
    <xsl:template match="player-name"></xsl:template> 
    <xsl:template match="schema-version"></xsl:template> 
    <xsl:template match="player-uuid"></xsl:template> 
    <xsl:template match="log-end-date"></xsl:template> 
    <xsl:template match="//entry"> 
     <xsl:text>"</xsl:text> 
     <xsl:value-of select="normalize-space(page)"/><xsl:text/> 
     <xsl:text>","</xsl:text> 
     <xsl:value-of select="normalize-space(path)"/><xsl:text/> 
     <xsl:text>","</xsl:text> 
     <xsl:value-of select="normalize-space(in)"/><xsl:text/> 
     <xsl:text>","</xsl:text> 
     <xsl:value-of select="normalize-space(out)"/><xsl:text/> 
     <xsl:text>"&#10;&#13;</xsl:text> 
<xsl:text disable-output-escaping = "yes" > 
</xsl:text> 
</xsl:template> 
</xsl:stylesheet> 

我喂到这些下面的C＃控制台应用程序将其转换成一个CSV并写入到一个文件：

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.IO; 
using System.Xml; 
using System.Xml.Xsl; 

namespace xml2csv 
{ 
    class Program 
    { 
     static int Main(string[] args) 
     { 
      if (args.Length != 3) 
      { 
       System.Console.WriteLine("Wrong number of aruguments"); 
       return -1; 
      } 

      string xmlFile = args[0]; 
      string xslFile = args[1]; 
      string outputFile = args[2]; 

      //Create a new XML document and load the XML file 
      XmlDocument xmlDoc = new XmlDocument(); 
      xmlDoc.Load(xmlFile); 
      //Create an XSLT object and load the XSLT file    
      XslCompiledTransform xslTran = new XslCompiledTransform(); 
      xslTran.Load(xslFile); 
      // This is for generating the output 
      XmlTextWriter writer = new XmlTextWriter(outputFile, System.Text.Encoding.ASCII); 
      //Apply the transformation and write disk 
      xslTran.Transform(xmlDoc, null, writer); 
      //Close the writer 
      writer.Close(); 

      return 1; 

     } 
    } 
} 

结果是p产品是：

"Page1","Path1","2012-08 16T23:59:52.170-05:00","2012-08-17T00:00:00.186-05:00" 
"Page2","Path2","2012-08-17T00:00:00.186-05:00","2012-08-17T00:00:08.561-05:00" 

我想要的是预先记录结束日期的兄弟节点值永远记录入口节点。所以输出看起来像这样：

"2012-08-17T23:59:59.999-05:00","Page1","Path1","2012-08 16T23:59:52.170-05:00","2012-08-17T00:00:00.186-05:00" 
"2012-08-17T23:59:59.999-05:00","Page2","Path2","2012-08-17T00:00:00.186-05:00","2012-08-17T00:00:08.561-05:00" 

任何帮助，将不胜感激。

Answer 1

只需添加：

<xsl:value-of select="concat('&quot;',normalize-space(../log-end-date),'&quot;')"/> 

为您的模板entry的第一个孩子。