2014-11-02 68 views
0

我正在创建一个LWJGL策略游戏,并且我正在实现多人游戏。Java网络 - java.net.BindException

现在游戏只是生成一些不同的瓷砖类型的世界。

我想我现在应该开始实现网络连接,让服务器生成世界,所有客户加入下载世界并加载它(尽管游戏几乎不可玩),以便更容易地实现更高级的以后的东西。现在解决问题!

我对网络实施,由DesignsbyZephyr提出看these教程,但我得到这个错误:

java.net.BindException: Address already in use: Cannot bind 
    at java.net.DualStackPlainDatagramSocketImpl.socketBind(Native Method) 
    at java.net.DualStackPlainDatagramSocketImpl.bind0(Unknown Source) 
    at java.net.AbstractPlainDatagramSocketImpl.bind(Unknown Source) 
    at java.net.DatagramSocket.bind(Unknown Source) 
    at java.net.DatagramSocket.<init>(Unknown Source) 
    at java.net.DatagramSocket.<init>(Unknown Source) 
    at java.net.DatagramSocket.<init>(Unknown Source) 
    at com.tdd12.eotu.net.GameServer.<init>(GameServer.java:22) 
    at com.tdd12.eotu.Game.<init>(Game.java:39) 
    at com.tdd12.eotu.Game.main(Game.java:121) 
Exception in thread "Thread-3" java.lang.NullPointerException 
    at com.tdd12.eotu.net.GameServer.run(GameServer.java:37) 

当我用同一个端口开始游戏两次。这听起来很奇怪,不是吗?

我不知道为什么,也许是因为我对网络编程不是很有经验(正如你可能已经理解的那样)。

这里是我使用的代码:
(代码放置在类和包,所以他们正确格式化我只是没有写在这里。)

GameServer.java:

// The socket 
private DatagramSocket socket; 
// The main game 
private Game game; 

// The constructor 
public GameServer(Game game) { 
    // Assign variables 
    this.game = game; 
    try { 
     this.socket = new DatagramSocket(9527); 
    } catch (SocketException e) { 
     e.printStackTrace(); 
    } 
} 

// Run the thread 
public void run() { 
    while(true) { 
     // The data to include in the packet (data to send) 
     byte[] data = new byte[1024]; 
     // The packet to send 
     DatagramPacket packet = new DatagramPacket(data, data.length); 
     // Recieve data from the server 
     try { 
      socket.receive(packet); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
     // Get the message 
     String message = new String(packet.getData()); 
     // Print the message 
     System.out.println("CLIENT [" + packet.getAddress().getHostAddress() + ":" + packet.getPort() + "] > " + new String(packet.getData())); 
     // If the message is equal to "ping" 
     if(message.trim().equalsIgnoreCase("ping")) { 
      // Send back a message with the text "pong" 
      sendData("pong".getBytes(), packet.getAddress(), packet.getPort()); 
     } 
    } 
} 

// Send data to the server 
public void sendData(byte[] data, InetAddress ipAddress, int port) { 
    // Create a new packet with the inputed data 
    DatagramPacket packet = new DatagramPacket(data, data.length, ipAddress, port); 
    // Send the packet to the server 
    try { 
     socket.send(packet); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
} 

GameClient.java:

// The IP address 
private InetAddress ipAddress; 
// The socket 
private DatagramSocket socket; 
// The main game 
private Game game; 

// The constructor 
public GameClient(Game game, String ipAddress) { 
    // Assign variables 
    this.game = game; 
    try { 
     this.socket = new DatagramSocket(); 
     this.ipAddress = InetAddress.getByName(ipAddress); 
    } catch (SocketException | UnknownHostException e) { 
     e.printStackTrace(); 
    } 
} 

// Run the thread 
public void run() { 
    while(true) { 
     // The data to include in the packet (data to send) 
     byte[] data = new byte[1024]; 
     // The packet to send 
     DatagramPacket packet = new DatagramPacket(data, data.length); 
     // Recieve data from the server 
     try { 
      socket.receive(packet); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
     // Print the data 
     System.out.println("SERVER > " + new String(packet.getData())); 
    } 
} 

// Send data to the server 
public void sendData(byte[] data) { 
    // Create a new packet with the inputed data 
    DatagramPacket packet = new DatagramPacket(data, data.length, ipAddress, 9527); 
    // Send the packet to the server 
    try { 
     socket.send(packet); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
} 

如果有人能帮助我,我将不胜感激。 谢谢!

+1

我觉得端口没有正常关闭。因此,当服务器第二次尝试侦听端口(它已被前一次运行占用)正在获取此错误。 – 2014-11-02 11:07:15

+0

好的,你知道如何关闭端口吗? – 2014-11-02 11:09:56

+0

我认为datagramSocket.close会做的。 http://download.java.net/jdk7/archive/b123/docs/api/java/net/DatagramSocket.html#close%28%29 – 2014-11-02 11:13:16

回答

0

正如Diptopol坝说,调用

DatagramSocket.close(); 

方法之前应用是闭固定的问题。谢谢Diptopol Dam!