SQL检查列中的所有值

Question

我在Oracle DB中具有下表。

ID VALUE 
----------- 
1 1 
1 2 
1 3 
2 1 
2 2 
3 1 
3 2 
3 3 
4 1 

如何选择的ID里面有所有3个值（1,2,3）

Answer 1

试试这个：

SELECT ID 
    FROM TABLENAME T 
WHERE EXISTS (SELECT * 
       FROM TABLENAME T1 
       WHERE T1.ID = T.ID AND T1.VALUE = '1') 
    AND EXISTS (SELECT * 
       FROM TABLENAME T2 
       WHERE T1.ID = T.ID AND T2.VALUE = '2') 
    AND EXISTS (SELECT * 
       FROM TABLENAME T3 
       WHERE T1.ID = T.ID AND T2.VALUE = '3') 

或

SELECT ID 
    FROM TABLENAME T 
WHERE (SELECT COUNT(*) 
      FROM (SELECT VALUE 
        FROM TABLENAME T1 
       WHERE T1.ID = T.ID 
       GROUP BY VALUE)) = 3; 

，其中3号的值可以通过

 SELECT COUNT(*) 
      FROM TABLENAME T1 
     GROUP BY VALUE 

所以这将是通用：

SELECT ID 
    FROM TABLENAME T 
WHERE (SELECT COUNT(*) 
      FROM (SELECT VALUE 
        FROM TABLENAME T1 
       WHERE T1.ID = T.ID 
       GROUP BY VALUE)) = (SELECT COUNT(*) 
             FROM TABLENAME T2 
            GROUP BY VALUE) 

Answer 2

下面是一个选项... HAVING子句中每个表达式计数被发现等于1，2或3，如果任何值的数量这些计数小于1，那么ID将不会被返回。

http://sqlfiddle.com/#!4/00fdc/8

SELECT ID 
FROM myTable 
GROUP BY ID 
HAVING 
    SUM(DECODE(VALUE, 1, 1, 0)) > 0 AND 
    SUM(DECODE(VALUE, 2, 1, 0)) > 0 AND 
    SUM(DECODE(VALUE, 3, 1, 0)) > 0 

EDIT - 规定值1，2或3个：

SELECT ID 
FROM myTable 
GROUP BY ID 
HAVING 
    SUM(DECODE(VALUE, 1, 1, 0)) > 0 AND 
    (
     SUM(DECODE(VALUE, 2, 1, 0)) > 0 OR 
     SUM(DECODE(VALUE, 3, 1, 0)) > 0 
) 

Answer 3

从（选择ID，和（情况下，当值= 1，则1

选择ID作为'v1'，
总和（当值= 2然后1其他0结束的情况）作为'v2'，
总和（当值= 3然后1其他0结束的情况）作为'v3'
由ID ORAC组）作为最终
其中，V1> 0且V2> 0和v3> 0

Answer 4

有了这个选项，你会得到更多的比的ID，到你的应用程序选择您想要的列：

SELECT ID, 
    sum(CASE WHEN VALUE = 1 THEN 1 ELSE 0 END) AS ONE, 
    sum(CASE WHEN VALUE = 2 THEN 1 ELSE 0 END) AS TWO, 
    sum(CASE WHEN VALUE = 3 THEN 1 ELSE 0 END) AS THREE 
FROM MYTABLE 
    GROUP BY ID 
    HAVING ONE >= 1 AND TWO >= 1 AND THREE >= 1; 

或者，如果你的情况是特定的（只值1，2，3是可能的，而且没有重复值是允许的），那么你可以尝试以下操作之一：

SELECT ID, 
    count(VALUE) AS VALUECOUNT 
FROM MYTABLE 
    GROUP BY ID 
    HAVING VALUECOUNT = 3; 

我会以ca重新开始之前，如果您稍后想要添加其他值，则可能会产生副作用。但是，如果您目前的案例符合上述限制条件，仍然值得提出建议。

，当然，如果你不喜欢这些取中间数的想法，我围内的另一选择

SELECT ID FROM (
    ... 
) 

Answer 5

最简单的方式给了查询一般是这样的

SQL> ed 
Wrote file afiedt.buf 

    1 with x as (
    2 select 1 id, 1 val from dual union all 
    3 select 1 id, 2 val from dual union all 
    4 select 1 id, 3 val from dual union all 
    5 select 2 id, 1 val from dual union all 
    6 select 2 id, 2 val from dual union all 
    7 select 3 id, 1 val from dual union all 
    8 select 3 id, 2 val from dual union all 
    9 select 3 id, 3 val from dual union all 
10 select 4 id, 1 val from dual 
11 ) 
12 select id 
13 from x 
14 where val in (1,2,3) 
15 group by id 
16* having count(distinct val) = 3 
SQL>/

     ID 
---------- 
     1 
     3 

WHERE子句标识您感兴趣的值。HAVING子句告诉您需要存在多少这些值。例如，如果您想要所有具有3个值中的至少2个的行，则会更改HAVING子句以查找COUNT为2。

如果一个特定的val保证每id最多发生一次，则可以消除HAVING子句中的distinct。