你能让像这样任何给定的分钟数:
DateAdd(Minute, (DateDiff(minute, 0, getutcdate())/15) * 15, 0)
而不是使用getutcdate()
你可以用你的日期列,变量或表达式。另外,分钟数可以是一个变量。
declare @minutesQuantize int set @minutesQuantize = 15
DateAdd(Minute, (DateDiff(minute, 0, getutcdate())/@minutesQuantize) * @minutesQuantize, 0)
唯一的规则是日期差异必须适合一个整数I.e.少于20亿美元。这意味着如果没有更复杂的表达式,你就无法做到几秒或几毫秒。
如果您需要秒钟或毫秒做到这一点:
dateadd(ms, (datediff(ms, dateadd(day, datediff(day, 0, @date), 0), @date)/@msInterval)*@msInterval, dateadd(day, datediff(day, 0, @date), 0))
或者,如果你想换到一个函数是:
create function dbo.DateRoundMinutes(@dt datetime, @minutes int)
returns datetime
as begin
return DateAdd(Minute, (DateDiff(minute, 0, @dt)/@minutes) * @minutes, 0)
end
go
create function dbo.DateRoundMilliseconds(@dt datetime, @ms int)
returns datetime
as begin
return dateadd(ms, (datediff(ms, dateadd(day, datediff(day, 0, @dt), 0), @dt)/@ms)*@ms, dateadd(day, datediff(day, 0, @dt), 0))
end
您可以使用这样的:
select t.dt,
dbo.DateRoundMilliseconds(dt, 500) dt0_5Second, -- Half second
dbo.DateRoundMilliseconds(dt, 5000) dt5second, -- 5 second
dbo.DateRoundMilliseconds(dt, 15000) dt15Second,
dbo.DateRoundMilliseconds(dt, 90000) dt90Second,
dbo.DateRoundMinutes(dt, 2) dt2Minute,
dbo.DateRoundMinutes(dt, 5) dt5Minute,
dbo.DateRoundMinutes(dt, 15) dt15Minute,
dbo.DateRoundMinutes(dt, 90) dt90Minute
from
/* some table having a column dt */