2016-05-30 98 views
4

我需要通过JSON格式的组件来获得漏洞获取漏洞,但我已经用CVE Details API只是单一的弱点得到其中任何组件或东西,只描述。CVE详细API,通过组件

这里是链接的例子

http://www.cvedetails.com/json-feed.php?numrows=10&vendor_id=0&product_id=0&version_id=0&hasexp=0&opec=0&opov=0&opcsrf=0&opfileinc=0&opgpriv=0&opsqli=0&opxss=0&opdirt=0&opmemc=0&ophttprs=0&opbyp=0&opginf=0&opdos=0&orderby=3&cvssscoremin=0 

这里是JSON的一个例子:

{ 
    "cve_id": "CVE-2016-4951", 
    "cwe_id": "0", 
    "summary": "The tipc_nl_publ_dump function in net/tipc/socket.c in the Linux kernel through 4.6 does not verify socket existence, which allows local users to cause a denial of service (NULL pointer dereference and system crash) or possibly have unspecified other impact via a dumpit operation.", 
    "cvss_score": "7.2", 
    "exploit_count": "0", 
    "publish_date": "2016-05-23", 
    "update_date": "2016-05-24", 
    "url": "http://www.cvedetails.com/cve/CVE-2016-4951/" 
} 

是否有任何方式的组件的名称来获得漏洞? (新老)

回答