常规闭包实例化变量

是否可以使用闭包从值列表中创建一组变量？询问这样做的原因是基于（比如说）两个三四个或五个部分当然这里的代码不能正常工作清单上创建一些递归功能，但任何指针将helpful.then常规闭包实例化变量

def longthing = 'A for B with C in D on E' 
//eg shopping for 30 mins with Fiona in Birmingham on Friday at 15:00 
def breaks = [" on ", " in ", "with ", " for "] 
def vary = ['when', 'place', 'with', 'event'] 

i = 0 
line = place = with = event = "" 
breaks.each{ 
shortline = longthing.split(breaks[i]) 
longthing= shortline[0] 
//this is the line which obviously will not work 
${vary[i]} = shortline[1] 
rez[i] = shortline[1] 
i++ 
} 
return place + "; " + with + "; " + event 
// looking for answer of D; C; B

编辑>>

是的，我试图找到收拾这个，这是我在每个循环后做了更巧妙的方式

len = rez[3].trim() 
if(len.contains("all")){ 
len = "all" 
} else if (len.contains(" ")){ 
len = len.substring(0, len.indexOf(" ")+2) 
} 
len = len.replaceAll(" ", "") 
with = rez[2].trim() 
place = rez[1].trim() 
when = rez[0].trim() 
event = shortline[0]

，如果我决定到另一个项目添加到列表（我只是这样做）我必须记住其中[I]它是成功地提取它

这是再解析日期/次，然后用jChronic自然文本转换成公历信息，所以我就可以在谷歌日历设置一个事件，工人的部分

来源

2010-12-06 john renfrew

我重读了你的问题，我不明白你在做什么。我认为我的答案会对你有所帮助，但如果你能举一个你的手术结果的例子，我会更有帮助。 – hvgotcodes 2010-12-06 15:39:58

如何：

def longthing = 'A for B with C in D on E' 
def breaks = [" on ", " in ", "with ", " for "] 
def vary = ['when', 'place', 'with', 'event'] 
rez = [] 
line = place = with = event = "" 

breaks.eachWithIndex{ b, i -> 
    shortline = longthing.split(b) 
    longthing = shortline[0] 
    this[vary[i]] = shortline[1] 
    rez[i] = shortline[1] 
} 
return place + "; " + with + "; " + event

来源

2010-12-06 16:36:20 btiernay

Fab ...我失踪的一点是这[[vary] [i]] - 谢谢 – 2010-12-06 16:48:38

当你使用带有List和“each”的闭包时，groovy遍历List中的元素，将值放入列表中的“it”变量中。不过，既然你也想保持指数的跟踪，有可能也通过在索引中的常规eachWithIndex

http://groovy.codehaus.org/GDK+Extensions+to+Object

所以像

breaks.eachWithIndex {item, index -> 
    ... code here ... 
}

来源

2010-12-06 15:23:57 hvgotcodes

常规闭包实例化变量

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