2013-02-15 49 views
0

组由结果通过SUM我有3个表:MySQL的 - 2列

user(id, name, id_school) 
school(id, name) 
result(id_user, stage1, stage2) 

现在我想获得学校的排名 - 是2列的总和:stage1和stage2所有用户。

+1

请显示您已经尝试过的陈述。 – 2013-02-15 12:53:35

回答

0

试试这个查询。它只是assumption.please提供一些数据进行测试

SELECT 
    s.id, 
    s.name AS SchoolName 
    (r.S1 + r.S2) AS Rank 
FROM school as s 
LEFT JOIN user as u ON u.id_school = s.id 
LEFT JOIN (SELECT id_user , SUM(stage1) as S1 , SUM(stage2) FROM result GROUP BY id_user) as r ON r.id_user = u.id 
GROUP BY s.id 
ORDER BY Rank DESC 
0

我会做这样的事情:

SELECT school.name, SUM(result.result1 + result.result2) 
FROM school LEFT JOIN user ON (user.id_school = school.id) LEFT JOIN result ON (result.id_user = user.id) GROUP BY school.id 

希望它能帮助,祝你好运:)

2

显得过于简单:

select s.name as school, sum(stage1)+sum(stage2) as rank 
    from result r 
    join user u on u.id=r.id_user 
    join school s on s.id=u.id_school 
group by s.id 

我真的希望你有索引。

+0

isnt s.name应该在groupby子句中吗? – DevelopmentIsMyPassion 2013-02-15 13:14:30

+0

@AshReva不在mysql中,在这里称之为“优化”) – 2013-02-15 13:16:08

+0

看来我确实错过了:( – DevelopmentIsMyPassion 2013-02-15 13:16:26