在单个javascript数组中添加很多javascript数组

Question

UPDATE! ADDING PHP code 

<?php 
    $tq_array = array(); 
    $c_array = array(); 
    $o1_array = array(); 
    $o2_array = array(); 
    $o3_array = array(); 
    $questions = mysql_query("SELECT * FROM test WHERE exam_code = '$exam'"); 
     while($row = mysql_fetch_assoc($questions)){ 
     $tq_array[] = $row['test_question']; 
     $c_array[]= $row['correct_answer']; 
     $o1_array[] = $row['option_1']; 
     $o2_array[] = $row['option_2']; 
     $o3_array[] = $row['option_3']; 
     } 
     $tq_json = json_encode($tq_array); 
     $c_json = json_encode($c_array); 
     $o1_json = json_encode($o1_array); 
     $o2_json = json_encode($o2_array); 
     $o3_json = json_encode($o3_array); 
?> 

我的问题是我想将这个转换后的javascript数组（从php数组）添加到另一个存储。

var questioner = JSON.parse('<?= $tq_json; ?>'); 
var correct_ans = JSON.parse('<?= $c_json; ?>'); 
var option1 = JSON.parse('<?= $o1_json; ?>'); 
var option2 = JSON.parse('<?= $o2_json; ?>'); 
var option3 = JSON.parse('<?= $o3_json; ?>'); 

这就是我要添加代码

var i = 0 
for(i = 0; i <= obj1.length;i++){ 
    var questions = [ 
     [ /* this is the one that fix the counting of the questioners*/], 

     [[obj1[i], obj2[i], obj3[i], obj4[i], obj5[i]],"false",1], 



     ], 

    sec=20, 
    A; 
} 

我尝试循环使用循环，但它没有工作的存储。

我喜欢出现像这样（）

var questions = [ 
     [ /* this is the one that fix the questioner */], 

     [[obj1[i], obj1[i], obj1[i], obj1[i], obj1[i]],"false",1], 
     [[obj2[i], obj2[i], obj2[i], obj2[i], obj2[i]],"false",1], 
     [[obj3[i], obj3[i], obj4[i], obj3[i], obj3[i]],"false",1], 

      So on .... 


     ], 

    sec=20, 
    A; 

谢谢！

Answer 1

您正在通过obj1阵列为每次迭代构建一个新阵列。我们需要促进questions阵列的范围和推到它：

var i = 0 
var questions = []; 
for(i = 0; i <= obj1.length;i++){ 
    questions.push(
     [[obj1[i], obj2[i], obj3[i], obj4[i], obj5[i]],"false",1], 
    ); 
} 

Answer 2

我想你想创建一个多维数组也许更难读哪个，所以我建议你使用对象来代替。

但这里的答案应该帮助 JavaScript multidimensional array