SQL查询同一个表内连接消除重复

Question

我有这个表：

CREATE TABLE [BGIA].[INTCOL004VA](
[ID] [int] NOT NULL, 
[DATYEN] [varchar](18) NULL, 
[ZZRIDN] [varchar](8) NULL, 
[OQTIEF] [varchar](1) NULL, 
[OQMONE] [varchar](3) NULL, 
[ZZPONR] [varchar](3) NULL, 
[ZZNBRE] [varchar](15) NULL, 
[ZZPDSE] [varchar](22) NULL 
); 

    INSERT INTO INTCOL004VA VALUES 
('53671955', 'MC1141103006', '38565363', '1', '007', '010', '0', '0'), 
('53671956', 'MC1141103006', '38565363', '0', NULL, '020', '0', '0'), 
('53671957', 'MC1141103006', '38565363', '0', '007', '030', '1', '500'), 
('53671958', 'VT1141103010', '38565421', '1', '007', '050', '0', '0'), 
('53671959', 'VT1141103010', '38565421', '0', NULL, '100', '0', '0'), 
('53671960', 'ST1141103006', '38587542', '0', NULL, '010', '1', '500'), 
('53671961', 'ST1141103006', '38587542', '1', 'B01', '020', '5', '0'); 

记录由DATYEN，ZZRIDN和ZZPONR

我想这个规则更新表链接：

• 对于一个链接DATYEN，ZZRIDN如果ZZNBRE上的一行不是0并且ZZPDSE => OQTIEF = 0并且OQMONE = NULL
• 但是对于一个链接DATYNE，ZZRIDN如果所有行都是a在ZZNBRE和ZZPDSE和一个行r 0有OQTIEF = 1和OQMONE不是null =>适用于所有的行AF链接OQTIEF = 1和OQMONE =不空行

我不能做的OQMONE与INNER JOIN突然，我不知道如何成功

谢谢:)

编辑：对于为例，这样的：

('53671955', 'MC1141103006', '38565363', '1', '007', '010', '0', '0'), 
('53671956', 'MC1141103006', '38565363', '0', NULL, '020', '0', '0'), 
('53671957', 'MC1141103006', '38565363', '0', '007', '030', '1', '500') 

必须是：

('53671955', 'MC1141103006', '38565363', '0', NULL, '010', '0', '0'), 
('53671956', 'MC1141103006', '38565363', '0', NULL, '020', '0', '0'), 
('53671957', 'MC1141103006', '38565363', '0', NULL, '030', '1', '500') 

因为组MC1141103006和38565363有一行与ZZNBRE和ZZPDSE不为0

此：

('53671960', 'ST1141103006', '38587542', '0', NULL, '010', '1', '500'), 
('53671961', 'ST1141103006', '38587542', '1', 'B01', '020', '5', '0') 

必须是：

('53671960', 'ST1141103006', '38587542', '0', NULL, '010', '1', '500'), 
('53671961', 'ST1141103006', '38587542', '0', NULL, '020', '0', '0') 

因为组ST1141103006和38587542有一排用ZZNBRE和ZZPDSE不是0，而是将ZZNBRE设置为0，因为ZZPDSE为0

这：

('53671958', 'VT1141103010', '38565421', '1', '007', '050', '0', '0'), 
('53671959', 'VT1141103010', '38565421', '0', NULL, '100', '0', '0') 

必须是：

('53671958', 'VT1141103010', '38565421', '1', '007', '050', '0', '0'), 
('53671959', 'VT1141103010', '38565421', '1', '007', '100', '0', '0') 

因为所有的行具有ZZNBRE和ZZNBRE 0

我希望能准确地说，是不容易理解我猜:(

编辑2：其实我的查询是：

update v1 
set v1.zznbre = (case when v1.zzpdse = 0 then 0 else v1.zznbre end), 
v1.oqtief = (case when v1.zznbre = 0 and v2.zznbre = 0 and v1.zzpdse = 0 and v2.zzpdse = 0 then 1 else 0 end), 
v1.oqmone = (case when v1.zznbre = 0 and v2.zznbre = 0 and v1.zzpdse = 0 and v2.zzpdse = 0 then v2.oqmone else null end) 
from intcol004va v1 
inner join intcol004va v2 on v2.datyen = v1.datyen and v2.zzridn = v1.zzridn and v2.id <> v1.id 
where v2.oqtief = 1 and v2.oqmone is not null and v1.oqtief <> v2.oqtief 

但在所有情况下无法正常工作:(

Answer 1

如果将更新作为两个独立更新进行处理，它似乎会生成正确的答案集。 我包含一个结果表和代码，它将显示原始数据与您的描述中定义的所需结果表之间的比较。

接下来，它将执行两次更新，然后显示已加入的原始表和目标表，以证明它们已正确对齐。

CREATE TABLE [INTCOL004VA](
[ID] [int] NOT NULL, 
[DATYEN] [varchar](18) NULL, 
[ZZRIDN] [varchar](8) NULL, 
[OQTIEF] [varchar](1) NULL, 
[OQMONE] [varchar](3) NULL, 
[ZZPONR] [varchar](3) NULL, 
[ZZNBRE] [varchar](15) NULL, 
[ZZPDSE] [varchar](22) NULL 
); 

CREATE TABLE [R_INTCOL004VA](
[ID] [int] NOT NULL, 
[DATYEN] [varchar](18) NULL, 
[ZZRIDN] [varchar](8) NULL, 
[OQTIEF] [varchar](1) NULL, 
[OQMONE] [varchar](3) NULL, 
[ZZPONR] [varchar](3) NULL, 
[ZZNBRE] [varchar](15) NULL, 
[ZZPDSE] [varchar](22) NULL 
); 

INSERT INTO INTCOL004VA VALUES 
('53671955', 'MC1141103006', '38565363', '1', '007', '010', '0', '0'), 
('53671956', 'MC1141103006', '38565363', '0', NULL, '020', '0', '0'), 
('53671957', 'MC1141103006', '38565363', '0', '007', '030', '1', '500'), 
('53671958', 'VT1141103010', '38565421', '1', '007', '050', '0', '0'), 
('53671959', 'VT1141103010', '38565421', '0', NULL, '100', '0', '0'), 
('53671960', 'ST1141103006', '38587542', '0', NULL, '010', '1', '500'), 
('53671961', 'ST1141103006', '38587542', '1', 'B01', '020', '5', '0'); 

INSERT INTO [R_INTCOL004VA] VALUES 
('53671955', 'MC1141103006', '38565363', '0', NULL, '010', '0', '0'), 
('53671956', 'MC1141103006', '38565363', '0', NULL, '020', '0', '0'), 
('53671957', 'MC1141103006', '38565363', '0', NULL, '030', '1', '500'), 
('53671960', 'ST1141103006', '38587542', '0', NULL, '010', '1', '500'), 
('53671961', 'ST1141103006', '38587542', '0', NULL, '020', '0', '0'), 
('53671958', 'VT1141103010', '38565421', '1', '007', '050', '0', '0'), 
('53671959', 'VT1141103010', '38565421', '1', '007', '100', '0', '0') 


SELECT 
    D.ID, 
    D.DATYEN, 
    D.ZZRIDN, 
    D.OQTIEF, 
    E.OQTIEF AS CORRECT_OQTIEF, 
    D.OQMONE, 
    E.OQMONE AS CORRECT_OQMONE, 
    D.ZZPONR, 
    D.ZZNBRE, 
    D.ZZPDSE 
FROM 
    INTCOL004VA AS D 
INNER JOIN 
    R_INTCOL004VA AS E ON D.ID = E.ID 

UPDATE 
    INTCOL004VA 
SET 
    OQTIEF = 0, 
    OQMONE = NULL 
FROM 
    INTCOL004VA AS A 
INNER JOIN 
    (SELECT 
     B.DATYEN, 
     B.ZZRIDN 
    FROM 
     INTCOL004VA AS B 
    GROUP BY 
     B.DATYEN, 
     B.ZZRIDN 
    HAVING 
     SUM(CAST(B.ZZNBRE AS INT)) > 0 
    ) AS C ON A.DATYEN = C.DATYEN AND A.ZZRIDN = C.ZZRIDN 


UPDATE 
    INTCOL004VA 
SET 
    OQTIEF = 1, 
    OQMONE = C.OQMONE 
FROM 
    INTCOL004VA AS A 
INNER JOIN 
    (SELECT 
     B.DATYEN, 
     B.ZZRIDN, 
     MAX(ISNULL(B.OQMONE,'')) AS OQMONE 
    FROM 
     INTCOL004VA AS B 
    GROUP BY 
     B.DATYEN, 
     B.ZZRIDN 
    HAVING 
     SUM(CAST(B.OQTIEF AS INT)) > 0 
    ) AS C ON A.DATYEN = C.DATYEN AND A.ZZRIDN = C.ZZRIDN 


SELECT 
    D.ID, 
    D.DATYEN, 
    D.ZZRIDN, 
    D.OQTIEF, 
    E.OQTIEF AS CORRECT_OQTIEF, 
    D.OQMONE, 
    E.OQMONE AS CORRECT_OQMONE, 
    D.ZZPONR, 
    D.ZZNBRE, 
    D.ZZPDSE 
FROM 
    INTCOL004VA AS D 
INNER JOIN 
    R_INTCOL004VA AS E ON D.ID = E.ID 

有时只是把它分解成更小的块是更容易的方法来解决问题。