MySQL查询 - 分组值和Aggregrating

Question

我火了下面的查询到我的表：

SELECT code_ver, 
     platform_type, 
     category_name 
FROM builds 
WHERE runtype LIKE 'test' 
     AND platform_type NOT LIKE 'total'; 

+-----------+---------------+---------------+ 
| code_ver | platform_type | category_name | 
+-----------+---------------+---------------+ 
| 10.0.1.50 | 8k   | UMTS   | 
| 10.0.1.50 | 8k   | UMTS   | 
| 10.0.1.50 | 8k   | IP   | 
| 10.0.1.50 | 8k   | IP   | 
| 10.0.1.50 | 9k   | IP   | 
| 10.0.1.50 | 9k   | IP   | 
| 10.0.1.50 | 9k   | UMTS   | 
| 10.0.1.50 | 9k   | UMTS   | 
| 10.0.1.50 | 9k   | UMTS   | 
| 10.0.1.50 | 9k   | Stability  | 
| 10.0.1.50 | 9k   | Stability  | 
| 10.0.1.51 | 8k   | UMTS   | 
| 10.0.1.51 | 8k   | UMTS   | 
| 10.0.1.51 | 8k   | IP   | 
| 10.0.1.51 | 8k   | IP   | 
| 11.0.1.50 | 9k   | UMTS   | 
| 11.0.1.50 | 9k   | IP   | 
+-----------+---------------+---------------+ 

我火了下面的查询

SELECT code_ver, 
     platform_type, 
     Count(*) 
FROM builds 
WHERE runtype LIKE 'test' 
     AND platform_type NOT LIKE 'total' 
GROUP BY code_ver, 
      platform_type; 

+-----------+---------------+----------+ 
| code_ver | platform_type | count(*) | 
+-----------+---------------+----------+ 
| 10.0.1.50 | 8k   |  4 | 
| 10.0.1.50 | 9k   |  7 | 
| 10.0.1.51 | 8k   |  4 | 
| 11.0.1.50 | 9k   |  2 | 
+-----------+---------------+----------+ 

当我火了下面的查询

SELECT code_ver, 
     platform_type, 
     Count(*) 
FROM builds 
WHERE runtype LIKE 'test' 
     AND platform_type NOT LIKE 'total' 
GROUP BY code_ver, 
      platform_type, 
      category_name; 

+-----------+---------------+----------+ 
| code_ver | platform_type | count(*) | 
+-----------+---------------+----------+ 
| 10.0.1.50 | 8k   |  2 | 
| 10.0.1.50 | 8k   |  2 | 
| 10.0.1.50 | 9k   |  2 | 
| 10.0.1.50 | 9k   |  2 | 
| 10.0.1.50 | 9k   |  3 | 
| 10.0.1.51 | 8k   |  2 | 
| 10.0.1.51 | 8k   |  2 | 
| 11.0.1.50 | 9k   |  1 | 
| 11.0.1.50 | 9k   |  1 | 
+-----------+---------------+----------+ 

但我想（code_ver + platform_type + category_name）的唯一组合的计数，使得输出sh应该看起来像这样：

+-----------+---------------+----------+ 
| code_ver | platform_type | count(*) | 
+-----------+---------------+----------+ 
| 10.0.1.50 | 8k   |  2 | 
| 10.0.1.50 | 9k   |  3 | 
| 10.0.1.51 | 8k   |  2 | 
| 11.0.1.50 | 9k   |  2 | 
+-----------+---------------+----------+ 

有没有人可以给我一些建议。根据设定您所提供的结果

Answer 1

使用SQL内部查询。

SELECT ta.code_ver, 
    ta.platform_type, 
    Count(*) 
FROM (SELECT code_ver, platform_type 
     FROM builds 
     WHERE runtype LIKE 'test' 
      AND platform_type NOT LIKE 'total' 
     GROUP BY code_ver, platform_type, category_name) AS ta -- table alias 
GROUP BY ta.code_ver, ta.platform_type; 

Answer 2

，它看起来像你想也按category_name

SELECT code_ver, 
      platform_type, 
      Count(*) , 
      category_name 
    FROM builds 
    WHERE runtype LIKE 'test' 
      AND platform_type NOT LIKE 'total' 
    GROUP BY code_ver, 
       platform_type, 
       category_name;