按小时排序时显示完整日期时间

Question

我正在使用microsoft sql server。我正在努力按全职时间对结果进行排序。

我的原始数据看起来像这样：

TimeStamp       TotalOffered 
2012-04-16 08:00:00     18 
2012-04-16 08:30:00     34 
2012-04-16 09:00:00     30 
2012-04-16 09:30:00     68 

我被小时块数据的例子总和期间8点00分00秒分选是52，为9时○○分00秒的数据的总和是98，我已经把它细分了一天。

的代码，我是：

select datepart(hour,[TimeStamp]), SUM([TotalOffered]) 
from [my table] 
group by 
datepart(hour,[sus_CallPerformance_TimeStamp]), 
dateadd(d, 0, datediff(d, 0, [sus_CallPerformance_TimeStamp])) 

我试图让数据充分展现时间戳，而不是仅仅一小时。

目前的结果显示为：

8 52 
9 98 

我想结果显示为：

2012-04-16 08:00:00 52 
2012-04-16 09:00:00 98 

谢谢

Answer 1

SELECT DATEADD(HOUR, DATEPART(HOUR, TimeStamp), DATEDIFF(DAY, 0, TimeStamp)) [TimeStamp], 
     SUM(TotalOffered) [TotalOffered] 
FROM [My Table] 
GROUP BY DATEADD(HOUR, DATEPART(HOUR, TimeStamp), DATEDIFF(DAY, 0, TimeStamp)) 
ORDER BY [TimeStamp] 

Answer 2

试试这个：

declare @t table (ts datetime, od int) 
insert into @t (ts, od) values ('2012-04-16 08:00:00', 18) 
insert into @t (ts, od) values ('2012-04-16 08:30:00', 34) 
insert into @t (ts, od) values ('2012-04-16 09:00:00', 30) 
insert into @t (ts, od) values ('2012-04-16 09:30:00', 68) 

select * from @t 


select 
    dateadd(hour, datepart(hour, ts), cast(floor(cast(ts as real)) as datetime)) as solution, 
    sum(od) 
    from @t 
    group by dateadd(hour, datepart(hour, ts), cast(floor(cast(ts as real)) as datetime)) 
    order by dateadd(hour, datepart(hour, ts), cast(floor(cast(ts as real)) as datetime)) 

Answer 3

DateTime字段可以转换为浮点值，其中整数代表日期，分数表示时间。如果通过24 multipy日期，那么整个数字将代表小时，具体如下：

SELECT CAST(FLOOR(CAST(TimeStamp AS FLOAT) * 24)/24.0 AS DateTime) AS Hr, SUM(TotalOffered) AS Total 
FROM [my table] 
GROUP BY FLOOR(CAST(TimeStamp AS FLOAT) * 24) 
ORDER BY FLOOR(CAST(TimeStamp AS FLOAT) * 24)