简短版本: 为什么shell脚本会在其生成的字符串中产生转义字符()嵌入(但不可见)?Shell脚本产生逃逸字符()与逃脱双重qoutes
详细版本:
我有产生Terraform命令并执行它的脚本。命令生成涉及使用变量来取代如下计算值:
...
AWS_VM_NUMBER=1
types="{"
array_limit=$((AWS_VM_NUMBER - 1))
for ((i = 0; i <= $array_limit; i++));
do
var=AWS_INSTANCE_TYPE_${i+1}
types=${types}"\"$i\"=\"${!var}\","
done
instance_types_array=${types%,}"}"
echo $instance_types_array ## prints {"0"="t2.small"} which is the correct fromat
...
# Now, executing a terraform command like this (please ignore the other variables as they exist else where in the code)
terraform apply -var \'access_key=$AWS_ACCESS_KEY\' \
-var \'secret_key=$AWS_SECRET_KEY\' \
-var \'instance_count=$AWS_VM_NUMBER\' \
-var \'region=$AWS_REGION\' \
-var \'instance_types=$instance_types_array\'
当执行terraform命令时,得到下面的错误:
invalid value "'instance_types={\"0\"=\"t2.small\"}'" for flag -var: Cannot parse value for variable ("{\"0\"=\"t2.small\"}'") as valid HCL: At 1:21: illegal char
如果我把该命令在一个变量和回声它,它打印没有反斜杠。但是,如果我复制它并在终端中手动执行它,我会得到相同的错误。它只会在我删除双引号并手工输入时才起作用!
是的,谢谢:) – Sami