如何根据搜索字符串获取所有记录在sql

Question

我想根据搜索字符串获取所有记录

E.G.

列名：FileName

MasterRoomTwo.jpg 
BedRoom.png 
MasterbedRoom.gif 

，并在简单的场景，我可以使用

Declare @FileName nvarchar(60) = NULL 
set @FileName = '.jpg' 

SELECT * 
FROM JobAttachment 
WHERE AND Tags LIKE '%' + ISNULL(@FileName ,FileName ) + '%' 
ORDER BY updated DESC 

但对我来说，我会得到这样的

set @FileName = '.jpg,.Png,gif' 

那么如何让像查询这个？

任何帮助将不胜感激。

感谢

Answer 1

试试这个。 拆分输入字符串和使用charindex

SELECT 'MasterRoomTwo.jpg' a INTO #temp UNION 
SELECT 'BedRoom.png' UNION 
SELECT 'MasterbedRoom.gif' 

DECLARE @FileName NVARCHAR(60) 

SET @FileName = '.jpg,.Png,gif' 

SELECT * 
FROM #temp 
     JOIN (SELECT Rtrim(Ltrim(Split.a.value('.', 'VARCHAR(100)'))) fs 
        FROM (SELECT Cast ('<M>' + Replace(@FileName, ',', '</M><M>') 
             + '</M>' AS XML) AS Data) AS A 
          CROSS APPLY Data.nodes ('/M') AS Split(a)) ad 
on Charindex(fs, a) > 0 

Answer 2

试试这个：

SELECT * 
FROM JobAttachment a 
     JOIN (SELECT t1.nod.value('.', 'varchar(50)') tags 
      FROM (SELECT Cast('<N>.' 
           + Replace(Replace(@FileName, '.', ''), ',', '</N><N>.') 
           + '</N>' AS XML) AS format) t 
        CROSS APPLY format.nodes('/N') AS t1(nod) 
      WHERE t1.nod.value('.', 'varchar(50)') <> '.') fileformat 
     ON a.tag LIKE ('%' + fileformat.tags + '%') 

Answer 3

您可以创建动态的条件

Declare @FileName nvarchar(60) = NULL 
set @FileName = '.jpg,.Png,gif' 


--append a comma to the string to get correct results with empty strings 
--or strings with a single value (no commas) 
SET @FileName = @FileName + ','; 

declare @x XML 
declare @FileSearch nvarchar(max) 
select @x = cast('<F>' + replace (@FileName,',','</F><F>') + '</F>' as xml)  
select @FileSearch = stuff(isnull(@FileSearch , '') + 
        ' OR FileName Like ''%'+ isnull(t.value('.','nvarchar(60)'),'') 
        +'%''' ,1,3,'') 
from @x.nodes('/F') as x(t) 

然后创建动态查询，从而获得所需的结果：

set @sql = 'select * from test where ' -- entire query goes here 
      + @FileSearch 

exec sp_executesql @sql 

DEMO