无法比拟的字符串从文件用java字符串读

Question

我读Java中的文件，该文件具有.lab扩展，基本上是用UTF字符的文本文件，其内容如下：

 
0.100904  125 SIL 
0.392625  125 तुझ्_beg 
0.622405  125 या_end 
0.623404  125 SIL 
0.946096  125  ले_beg 
1.120000  125 मळ्_mid 
1.362698  125 या_end 
1.363697  125 SIL 

但在程序当我比较如下：

arr[2].equals("SIL") 

它不起作用。 整个java代码如下：

public class SyllableCount 
{ 

static final File labDir = new File("/media/sda6/tts/programs/MyWork/silence_handling/labs_4"); 
static final HashMap<String, ArrayList<Float>> terminalSyllMap = new HashMap<String, ArrayList<Float>>(); 

public void accessFilesForFolder(final File labDir) 
{ 
    System.out.println("in method"); 
    for (final File labFile : labDir.listFiles()) 
    { 
     if (labFile.isDirectory()) 
     { 
      accessFilesForFolder(labFile); //for recursive operation 
     } else 
     { 

      System.out.println(labFile.getName()); 
      BufferedReader br = null; 
      String[] syllable = new String[100];//just an example-you have to initialize it big enough to hold all lines 
      float[] timeFrame = new float [100]; 

      String sCurrentLine; 
      try 
      { 
       //br = new BufferedReader(new FileReader(labFile)); 
       br = new BufferedReader(new InputStreamReader(new FileInputStream(labFile), "UTF8")); 


       int lineNo=0; 
       while ((sCurrentLine = br.readLine()) != null) 
       { 
        String[] arr = sCurrentLine.split(" "); 
        //for the first line it'll print 

        if(arr[0].equalsIgnoreCase("#")) 
        { 
         lineNo++; 
         continue; 
        } 


         //entering them into separate arrays 
         timeFrame[lineNo] = Float.parseFloat(arr[0]); 
         syllable[lineNo] = arr[2]; 

         lineNo++; 

       } 

       br.close(); 
       populateMaps(timeFrame, syllable, lineNo); 

       } catch (Exception e) { 
        // TODO Auto-generated catch block 
        e.printStackTrace(); 
       } 

     } 
     } 
    System.out.println(terminalSyllMap); 
} 

public void populateMaps(float[] timeFrame,String[] syllable, int lineNo) throws Exception 
{ 



    String syllval; 
    float duration; 
    ArrayList<Float> timeframeArray; 
    for(int i=0; i<lineNo-1; i++) 
    { 

     //System.out.println(syllable[i+1]); 
     if (syllable[i+1].equals("SIL")) 
     { 
      syllval = syllable[i]; 
      duration = timeFrame[i+1] - timeFrame[i]; 
      if(terminalSyllMap.containsKey(syllval)) 
      { 
       timeframeArray = terminalSyllMap.get(syllval); 
      } 
      else 
      { 
       timeframeArray = new ArrayList<Float>(); 
      } 
      timeframeArray.add(duration); 
      terminalSyllMap.put(syllval, timeframeArray); 
     } 
    } 
} 

public static void main(String[] args) 
{ 
    // 
    SyllableCount run = new SyllableCount(); 
    run.accessFilesForFolder(labDir); 

} 





} 

任何帮助将不胜感激。

Answer 1

尝试：

final String[] arr = sCurrentLine.split("\\s+");