如果你有这样的:读字符串中的字符串
foreach(string n in txtList)
{
Console.WriteLine(n);
}
输出:
[HKEY_Something_Something\.abc]
[HKEY_Something_Something\.defg]
[HKEY_Something_Something\.ijklmn]
如何获得之间有什么 “”和“]”?
如果你有这样的:读字符串中的字符串
foreach(string n in txtList)
{
Console.WriteLine(n);
}
输出:
[HKEY_Something_Something\.abc]
[HKEY_Something_Something\.defg]
[HKEY_Something_Something\.ijklmn]
如何获得之间有什么 “”和“]”?
如果它总是遵循格式,改变你的代码应该输出w帽子你想要的:
foreach(string n in txtList)
{
int startindex = n.IndexOf(@"\.") + 2;
Console.WriteLine(n.Substring(startindex, n.Length-startindex-1));
}
简单而有用:)谢谢! – 2012-02-15 10:33:30
尝试
foreach(string n in txtList)
{
string str[] = n.Split('.');
if (str.Length > 0)
{
string s = str[str.Length-1];
Console.WriteLine(s.Substring(0, s.Length-1));
}
}
@Oliver:str在这里是一个数组... – 2012-02-15 10:33:57
您可以使用正则表达式:
var s = @"[HKEY_Something_Something\.abc]";
var result = Regex.Match(s, @"(?<=\.)[^]]*(?=]$)")
// result == "abc"
正则表达式的简短解释:
(?<=\.) - preceded by a dot
[^]]* - anything which isn't a ']'
(?=]$) - followed by a ']' and the end of the string
var per = n.IndexOf("."); // may need to add +1 to get past . index.
var len = n.IndexOf("]") - per - 1;
var val = n.Substring(per, len);
答案很简单:
int dotPosition = n.LastIndexOf(".") + 1; // +1 because we start AFTER the dot.
int bracketPosition = n.LastIndexOf("]"); // can do "n.Length - 2" too.
Console.WriteLine(n.Substring(dotPosition, bracketPosition - dotPosition));
更复杂的答案:使用正则表达式。
也可以!谢谢! :) – 2012-02-15 10:33:44
例如用正则表达式:
Match match = Regex.Match(n, @"\.(.*)\]");
string result = match.Groups[1].Value;
这取决于..有永远只有一个点?一个反斜杠? – IanNorton 2012-02-15 10:14:37
阅读关于正则表达式 – 2012-02-15 10:15:21