mySQL - 正确的方法来做到这一点？

我想你可以我是一个老屁，但一直是我做了mySQL（不是我自己的专家），我敢肯定有更好的方法来写这个。希望你能帮助我。mySQL - 正确的方法来做到这一点？

SELECT 
    (SELECT MIN(bank_id) FROM bank) AS MinBank, 
    (SELECT MAX(bank_id) FROM bank) AS MaxBank, 
    (SELECT bank_id FROM bank WHERE bank_id = $UserID) AS OldBankID, 
    (SELECT bank_name FROM bank WHERE bank_id = OldBankID) AS OldBankName, 
    (SELECT bank_interest FROM bank WHERE bank_id = OldBankID) AS OldBankInterest, 
    (SELECT bank_fees FROM bank WHERE bank_id = OldBankID) AS OldBankFees, 
    (SELECT bank_pic_url FROM bank WHERE bank_id = OldBankID) AS BankPic 
    (SELECT bank_id FROM bank HAVING bank_id > (SELECT bank_id FROM users WHERE uid = $UserID) LIMIT 1) AS NewBankID, 
    (SELECT bank_name FROM bank WHERE bank_id = NewBankID) AS NewBankName, 
    (SELECT bank_interest FROM bank WHERE bank_id = NewBankID) AS NewBankInterest, 
    (SELECT bank_fees FROM bank WHERE bank_id = NewBankID) AS NewBankFees, 
    (SELECT bank_cost FROM bank WHERE bank_id = NewBankID) AS NewBankCost, 
FROM dwrel_bank LIMIT 1

基本上它是2个表：（用户）表1 - 检索Bank_ID（客户的旧ID）（银行）表2 - 获取他们的老银行信息和检索他们的下一个 “升级” 的可用性。

它确实给我提供了我想要的信息，但是想知道我是否可以通过某种方式改善这种情况。

谢谢！

来源

2012-03-15 sgkdnay

它的混乱，在一个地方，你变老从银行表'银行ID在另一个你从'用户表' – 2012-03-15 05:08:09

基本上这：从用户的表中获取Bank_ID。然后使用此bank_id并从银行表中获取信息。然而，从银行表格中，我想要从同一张银行表中获得2个“重复”信息：他们当前的银行信息和他们的下一个潜在的“升级”。 – sgkdnay 2012-03-15 05:11:43

可以更改基于oldBankId第一部分如下

select bank_id OldBankId ,bank_name OldBankName, bank_interest OldBankInterest , 
bank_fees OldBankFees, bank_pic_url as BankPic from bank 
where bank_Id =(select bank_id from bank where bank_id= $user_id)

你与newBank ID来加入这个并使用相同的语法如上

来源

2012-03-15 05:19:45

当你说join时，你的意思是UNION还是LEFT JOIN？不太确定。 – sgkdnay 2012-03-15 05:39:09

在id =（从表中选择ID，其中id> $ userId限制为1）' – 2012-03-15 05:44:32

希望你能够表现出自己的方式，我有点失落尝试它自己哈哈，在此先感谢:) – sgkdnay 2012-03-15 06:46:45

mySQL - 正确的方法来做到这一点？

回答

相关问题