2017-03-08 105 views
0

所以我要在Django这两种型号:Django的模型外键查询

class Course(models.Model): 

    def get_image_path(self, filename): 
     return os.path.join('courses', str(self.slug), filename) 

    def __str__(self): 
     return self.name 

    def save(self, *args, **kwargs): 
     self.slug = slugify(self.name) 
     super(Course, self).save(*args, **kwargs) 

    name = models.CharField(max_length=255, verbose_name="Nombre") 
    description = models.CharField(max_length=255,  verbose_name="Descripción") 
    price = models.DecimalField(max_digits=12,decimal_places=2, verbose_name="Precio") 
    slug = models.SlugField(blank=True, max_length=255) 
    icon_img = models.ImageField(upload_to=get_image_path, blank=True, null=True, verbose_name="Imagen") 
background_color = ColorField(default="#026085") 


    class Meta: 
     verbose_name = "curso" 
     verbose_name_plural = "cursos" 

class UserCourse(models.Model): 
    user = models.ForeignKey(User) 
    course = models.ForeignKey(Course) 

所以每当一个用户“购买”的课程,它存储在UserCourse。我有一个观点,系统显示用户购买的所有课程列表。这是视图代码:

def user_course_list_view(request, username): 
    context_dict = {} 
    try: 
     user_courses = UserCourse.objects.filter(user=request.user).course_set 
     context_dict['courses'] = user_courses 
     context_dict['heading'] = "Mis cursos" 
    except: 
     context_dict['courses'] = None 
     context_dict['heading'] = "Mis cursos wey" 
    return render(request, 'courses/course_list.html', context=context_dict) 

我不知道哪里是错误,我似乎无法捕捉到了异常

+0

'UserCourse.objects.filter(user = request.user).course_set'这是什么意思?查询集不会有一个名为'course_set'的字段。在这种情况下,移除异常处理并查看代码破坏的位置 – karthikr

+0

user_courses = UserCourse.objects.filter(user = request.user).course_set.all() 这是否适合您? – n1cko

回答

2

TL(使用泊坞窗的Django IM);博士

像这样的东西应该工作。

usercourse_objects = UserCourse.objects.filter(user=request.user).select_related('course') 
user_courses = [x.course for x in usercourse_objects] 

说明

有多种方法可以做到这一点,但一个方法是先得到所有当前用户的UserCourse对象:

usercourse_objects = UserCourse.objects.filter(user=request.user) 

然后,对每个UserCourse对象,获取相关信息Course

user_courses = [x.course for x in usercourse_objects] 

现在,第二行会导致N个数据库查询(每次我们按照course外键关系进行查询。为了防止这种情况,第一行可以更改为:

usercourse_objects = UserCourse.objects.filter(user=request.user).select_related('course') 

该预填充UserCourse对象的属性course。有关select_related()的更多信息可以发现here