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如何在MAX之前选择第一,第二或第三个值?MySQL之前的MySQL选择值
通常我们用为了做到这一点,并限制
SELECT * FROM table1
ORDER BY field1 DESC
LIMIT 2,1
,但我目前的查询我不知道如何使它...
样品表
+----+------+------+-------+
| id | name | type | count |
+----+------+------+-------+
| 1 | a | 1 | 2 |
| 2 | ab | 1 | 3 |
| 3 | abc | 1 | 1 |
| 4 | b | 2 | 7 |
| 5 | ba | 2 | 1 |
| 6 | cab | 3 | 9 |
+----+------+------+-------+
我将这个查询的每个类型的名称与最大数联系起来
SELECT
`table1b`.`name`
FROM
(SELECT
`table1a`.`type`, MAX(`table1a`.`count`) AS `Count`
FROM
`table1` AS `table1a`
GROUP BY `table1a`.`type`) AS `table1a`
INNER JOIN
`table1` AS `table1b` ON (`table1b`.`type` = `table1a`.`type` AND `table1b`.`count` = `table1a`.`Count`)
,我想多了一个额外的列值为命名之前最大(计数)
所以结果应该是
+------+------------+
| name | before_max |
+------+------------+
| ab | 2 |
| b | 1 |
| cab | NULL |
+------+------------+
请问,如果事情是不明确;)
谢谢:)这是真棒,我无法弄清楚,也该给我一个线索如何米更复杂的查询:) – davispuh 2011-06-10 20:55:40