Python的修改CSV数据

Question

我有一个文件，该文件看起来像这样（2/3的连续的行，即随机组合）：

String A 
String B 
String C 
<Blank Row> 
String D 
String E 
<Blank Row> 
String F 
String G 
String H 
<Blank Row> 
String I 
String J 
String K 
<Blank Row> 
String L 
String M 

我想当存在连续3行中的输出文件以除去中间排并转置剩余的2行。如果只有2行，它们应该转置。最终的结果应该是这样的。

String A,String C 
String D,String E 
String F,String H 
String I,String K 
String L,String M 

任何指针如何做到这一点？

Answer 1

您可以使用groupby和count从itertools模块以及list comprehension。

这个答案有点不好意思，但是要诀窍。请参阅评论以更好地理解背后的逻辑。

我假设你的投入，你是在一个名为my_input_file文件给出了输入和输出文件被称为output_file：

from itertools import groupby, count 

# Read the file and split by the space between Value and its number 
# Leave the case where the empty string '' exists without splitting its spaces 
with open("my_input_file", 'r') as f: 
    data = (k.split() if k != '' else k for k in f.read().splitlines()) 

# Group the fields splitted, which are lists, in data 
# And separate them by the field where the string 'Blank' exists 
sub = [list(v) for _, v in groupby(data, lambda x: isinstance(x, list))] 

final = [] 
for elm in sub: 
    # if the lenght of the grouped elements is > 1 
    if len(elm) >1: 
     # Convert the number of the values into an int 
     # For further calculations 
     dd = map(lambda x: [x[0], int(x[1])], elm) 

     # Group the consecutive numbers of elem 
     for _,v in groupby(dd , lambda x,y=count(): x[1] - next(y)): 
      # If there is a consecutive numbers 
      bb = list(v) 
      if len(bb) >1: 
       # Conveert them into strings. Then, append the first and the final one to the final list 
       final.append(' '.join(map(str, bb[0])) + ',' + ' '.join(map(str, bb[-1]))) 

      # If there is'nt any consecutif numbers. Append the element to the final list 
      else: 
       final.append(" ".join(map(str, bb[0]))) 


# create the output file 
with open("output_file", 'a') as f: 
    for k in final: 
     f.write(k + '\n') 

这段代码输出包含一个文件：

Value 1,Value 3 
Value 4,Value 5 
Value 6,Value 8 
Value 9,Value 11 
Value 12,Value 13 

测试此代码，并留下您的反馈，如果您有任何或可能，请报告错误，如果你发现任何他们。

编辑：

根据上次编辑。

如果输入的文件是：

What Test 
Makes No Sense 
is This 

My name 
Is Sample 123 

Your Name 
is ABC 2134 

What is you 
technical question don't know 
name? 

诀窍，就是这么简单。你可以做这样的事情，只有groupby利用itertools模块：

from itertools import groupby 

with open("my_input_file", 'r') as f: 
    data = f.read().splitlines() 

final = [list(v) for _, v in groupby(data, lambda x: x != '')] 

with open("ouput_file", 'a') as f: 
    for k in final: 
     if k != ['']: 
      f.write(k[0] + ',' + k[-1] + '\n') 

而且，你的输出文件将是：

What Test ,is This 
My name ,Is Sample 123 
Your Name ,is ABC 2134 
What is you ,name? 

Answer 2

为了旋转：你知道所有线路末

with open("PATH TO FILE.txt", r) as file: 
    input = file.read() 
    input.replace("\n", "") 

对于只有空格，或以确定它们的线条有一个新的生产线。到目前为止：

with open("PATH TO FILE.txt", r) as file: 
     input = file.read() 
     if not line.strip(): 
      input.replace("\n", "") 

，你可以保持一个计数或做一个while循环，所以你计数，直到你打，只有空格行和当计数把每行一个列表或东西， 如果计算3抓住第一和第三，否则抓住两者。请记住重置计数