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我不是一个编码器，所以我问你们，如果你知道我怎么能解决我的问题。 在arduino中，我用DS18B20传感器编写了第一个程序，该程序通过MQTT网络程序在openHAB中显示温度。 第二个程序是同样的东西（openhab，mqtt）只是开关灯，这意味着当我按下开关时，灯或LED通过Arduino中的回调函数打开或关闭。 另外这两个程序工作得很好，但是当我试图将它们连接在一起时，它不起作用，因为我想。在我看来，问题在于循环功能。当我按下开关ON或OFF时，有时（很少）我可以打开或关闭指示灯。所以我的问题是...什么是错的？循环是否有问题，因为arduino不能同时在循环中处理两件事情？它可以解决，我真的不知道下一步该怎么做。请帮助我，并提前致谢！arduino循环不能使用两个进程
#include <OneWire.h>
#include <DallasTemperature.h>
#include <SPI.h>
#include <PubSubClient.h>
#include "WiFiEsp.h"
// Emulate Serial1 on pins 3/2 if not present
#ifndef HAVE_HWSERIAL1
#include "SoftwareSerial.h"
SoftwareSerial Serial1(3, 2); // RX, TX
#endif
char ssid[] = "SSID; // your network SSID (name)
char pwd[] = "password"; // your network password
float temp = 0;
byte server[] = { 192, 168, 1, 71 }; // IP Address of your MQTT Server
WiFiEspClient espClient;
PubSubClient client(espClient);
#define ONE_WIRE_BUS 4
// Setup a oneWire instance to communicate with any OneWire devices (not just Maxim/Dallas temperature ICs)
OneWire oneWire(ONE_WIRE_BUS);
// Pass our oneWire reference to Dallas Temperature.
DallasTemperature sensors(&oneWire);
void callback(char* topic, byte* payload, unsigned int length) {
Serial.println("Callback");
Serial.println(topic);
Serial.println(length);
Serial.write(payload,length);
Serial.println();
if (strcmp(topic,"home/luc")==0) {
if (payload[0] == '0')
{
digitalWrite(7, LOW);
delay(100);
client.publish("home/luc/state","OFF");
}
else if (payload[0] == '1')
{
digitalWrite(7, HIGH);
delay(100);
client.publish("home/luc/state","ON");
}
}
}
void temperaturni_senzor()
{
sensors.requestTemperatures();
temp = sensors.getTempCByIndex(0);
Serial.print("Temperatura je: ");
Serial.println(temp); // Why "byIndex"? You can have more than one IC on the same bus. 0 refers to the first IC on the wire
//Update value every 1 sec.
client.publish("home/temperature", String(temp).c_str(),TRUE);
delay(50);
}
void reconnect() {
// Loop until we're reconnected
while (!client.connected()) {
Serial.print("connecting to mqtt...");
// Attempt to connect
if (client.connect("ESP8266 client")) {
Serial.println("connection good");
// ... and subscribe to topic
client.subscribe("home/luc");
} else {
Serial.print("failed, rc=");
Serial.print(client.state());
Serial.println(" try again in 5 seconds");
// Wait 5 seconds before retrying
delay(5000);
}
}
}
void setup()
{
Serial1.begin(9600);
Serial.begin(9600); //Begin serial communication
WiFi.init(&Serial1);
WiFi.begin(ssid, pwd);
client.setServer(server, 1883);
client.setCallback(callback);
if (client.connect("arduinoClient"))
{
Serial.println ("mqqt is connected");
client.publish("outTopic","hsubscribello world");
client.subscribe("home/luc"); // Subscribe to all messages for this device
client.subscribe("home/temperature");
}
pinMode(7, OUTPUT);
digitalWrite(7, LOW);
sensors.begin();
}
void loop()
{
client.loop();
if (!client.connected())
{
reconnect();
}
temperaturni_senzor();
}
}
编辑的问题，包括你的代码，所以我们不必猜测 – hardillb
有没有** **过程中的Arduino。 *你的意思是“arduino不能在同一时间在循环中处理两件事情”*？ Arduino按照您指定的顺序依次执行每个事件**。 –